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andrey2020 [161]
3 years ago
6

HELP ME ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing. Check ALL that apply.

Mathematics
1 answer:
Alexus [3.1K]3 years ago
5 0

Answer:

the answer would be D &F

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Dakota earned $15.75 in interest in Account A and $28.00 in Account B after 21 months. If the simple interest rate is 3.0 for Ac
klemol [59]
Answer: account B had the greater capital.
Step-by-step explanation:
The formula for determining simple interest is expressed as
I = PRT/100
Where
I represents interest paid on the amount deposited.
P represents the principal or amount deposited
R represents interest rate
T represents the duration in years.
Considering account A,
I = $15.75
T = 21 months = 21/12 = 1.75 years
R = 3%
Therefore,
15.75 = (P × 3 × 1.75)/100
15.75 = 0.0525P
P = 15.75/0.0525
P = 300
Considering account B,
I = $28
T = 21 months = 21/12 = 1.75 years
R = 4%
Therefore,
28 = (P × 4 × 1.75)/100
28 = 0.07P
P = 28/0.07
P = $400
Therefore, account B had the greater capital.
3 0
3 years ago
Read 2 more answers
The average summer temperature in Anchorage is 69°F. If the daily temperature is normally distributed with a standard deviation
Savatey [412]

Answer:

81.85%

Step-by-step explanation:

Given :

The average summer temperature in Anchorage is 69°F.

The daily temperature is normally distributed with a standard deviation of 7°F .

To Find:What percentage of the time would the temperature be between 55°F and 76°F?

Solution:

Mean = \mu = 69

Standard deviation = \sigma = 7

Formula : z=\frac{x-\mu}{\sigma}

Now At x = 55

z=\frac{55-69}{7}

z=-2

At x = 76

z=\frac{76-69}{7}

z=1

Now to find P(55<z<76)

P(2<z<-1)=P(z<2)-P(z>-1)

Using z table :

P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185

Now percentage of the time would the temperature be between 55°F and 76°F = 0.8185 \times 100 = 81.85\%

Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.

8 0
4 years ago
In a newspaper, it was reported that yearly robberies in Springfield were up 40% to 196 in 2013 from 2012. How many robberies we
oee [108]

Answer:

There were 140 robberies in Springfield in 2012.

Step-by-step explanation:

Let's marked (named) robberies in 2012 with x, which is worth 100%

196 robberies in 2013 worth 100% + 40% = 140%

Now we will make proportion

x : 196 = 100 : 140

When we multiply external and internal members we get

140 x = 196 · 100 => 140 x = 19600 => x = 19600/140 = 140

x = 140 robberies in 2012

5 0
3 years ago
Helpppp<br> Me<br> Please<br> Someone <br> Lol
RoseWind [281]

Answer:

14 is the answer

Step-by-step explanation:

hope it helps

6 0
3 years ago
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A steel company sells 48 tons of steel each year.
Elena L [17]

Answer:

I think its 16

Step-by-step explanation:


6 0
4 years ago
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