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AleksAgata [21]
3 years ago
11

A movie is 2 hours and 28 minutes long it starts at 7:50 a.m. at what time will the movie end​

Mathematics
2 answers:
Marina CMI [18]3 years ago
8 0

Answer:

10:18

Step-by-step explanation:

7:50+ 2=8:10

+8+8:18

2+8=10

10:18

LuckyWell [14K]3 years ago
4 0

Answer:

the answer is 10:18 a.m.

Step-by-step explanation:

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Solve x^2-8x+14=2x+7
LuckyWell [14K]

Answer:

Step-by-step explanation:

x²-8x+ 14 =2x+7

x² - 8x +14 - 2x - 7 = 0

x² - 10x  + 7 = 0

5 0
3 years ago
A bullet is fired straight up from a gun with initial velocity 1120 feet per second at an initial height of 8 feet. Use the form
Dafna1 [17]

Answer:

70 seconds

Step-by-step explanation:

Given that;

The initial velocity v_o of the bullet fired = 1120 ft/s

Initial height h = 8 feet

The expression to determine how many seconds it takes the bullet to hit the ground is:

h = -16t^2 +v_ot + 8

Thus;

Replacing the value of v_o =  1120 and h = 0 (i.e. when h =0) in the above expression; we have:

0= -16t^2 +(1120)t + 8

=  -16t^2 +(1120)t + (8-0)

= -16t² + 1120t + 8

mulitiply through by (-)

= 16t² -1120t - 8

Divide through by 8

= 2t² -  140t - 1

The above expression forms a quadratic equation.

where;

a = 2

b = -140

c = - 1

So, by using the quadratic formula \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}, we have:

= \dfrac{-(-140) \pm \sqrt{(-140)^2-4(2)(-1)}}{2(2)}

= \dfrac{140 \pm \sqrt{19600-(-8)}}{4}

= \dfrac{140 \pm \sqrt{19608}}{4}

= \dfrac{140 \pm 140}{4}

=\dfrac{140+ 140}{4} \ \ \ OR \ \ \  \dfrac{140-140}{4}

=\dfrac{280}{4} \ \ \ OR \ \ \  0

= 70

Thus, the time (in seconds) it took the bullet to it the ground = 70 seconds

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3 years ago
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Lunna [17]

Answer:

first off, welcome to brainly, second, your answer is 14.4

Step-by-step explanation:

5 0
3 years ago
Every possible cross section of a three-dimensional figure is a circle. What is the figure?
dsp73
A cross section is the shape we get when cutting straight through an object. In geometry it is the shape made when a solid is cut through by a plane. cylinder cross section.The cross section of this circular cylinder is a circle.
3 0
3 years ago
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NEED HELP ASAP!!! What is the interquartile range of the data set? Enter the answer in the box. Key: 1|5 means 15 A stem-and-lea
monitta
To find the interquartile range, you will list the data that is presented in the stem and leaf plot.

Find the median of the data (30.5)

Find the median of the lower half and the median of the upper half.

Subtract these two values.

The data are <u>20</u>, 25, 30, 30, 31, 40, 41, <u>49</u>.
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The interquartile range is 13.
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3 years ago
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