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nikklg [1K]
3 years ago
12

How would you compare the sizes of two balls

Mathematics
1 answer:
lozanna [386]3 years ago
6 0

Answer:

You could compare the mass of each ball and volume, You could also find the height of each ball or diamiter. I really hope this isnt satire.

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A spherical ball just fits inside a cylindrical can, 20 centimeters tall, with a diameter of 20 centimeters. Which expression gi
goldenfox [79]
Start with the volume equation for a sphere:

V=4/3pi•r^3

The dimensions of the cylinder allow for a sphere with a diameter of 20 centimeters, so the radius of this sphere will be 10 centimeters. Substituting this into the equation:

V=4/3pi•(10)^3

or the uppermost right answer (B).
8 0
4 years ago
Read 2 more answers
Let f(x) = -2x + 6 and g(x) = 5x - 7.
siniylev [52]

Answer:

a) 3x - 1

Step-by-step explanation:

f(x) + g(x)

(-2x + 6) + (5x - 7)

Drop the parentheses

-2x + 6 + 5x -7

5x and -2x can be combined as well as 6 and -7

So, 3x -1

7 0
3 years ago
Help needed with all pls
Olenka [21]
#5 is 5 days
40×5=200
200+150=250

20×5=100
100+150=250
3 0
3 years ago
Which is a solution of the system of equations shown?
taurus [48]

Answer:

  D.  (2, 0)

Step-by-step explanation:

The solutions are the two points of intersection of the graphs:

  (-2, -4) and (2, 0)

The latter of these corresponds to choice D, the one you have marked.

5 0
3 years ago
For what value of "a" will the product shown below have a purely imaginary value? (Show work please)
MakcuM [25]
If you expand out the brackets you get this,

(4+5i)(a+2i) = 4a + (5a)i + 8i - 10

The -10 comes from 5i * 2i.
Squaring i becomes -1.

Let's group the real stuff together,
and imaginary separately,

(4a - 10) + (5a + 8)i

For this to be purely imaginary,
the real part needs to be zero.

Therefore 4a - 10 = 0

Solve for a.
5 0
3 years ago
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