Answer:
#5) Its line “k”
Well to solve this you need to know what negative slopes are.
They decrease from height from left to right
And also a slope is always calculated like this
rise -> run
Think of it like a bed.
You have to wake up which means you have to rise and then you run to do whatever it is you gotta do.
Rise is going vertical and run is going horizontal.
So for line K you have it because since its negative its -3/1 so technically its -3 rise(basically fall since its negative), 1 run (right).
#6) 1/2 is the slope of line N. Or (c)
Well n is a potsive slope so we can automatically remove a and b.
And we can count like this, it started from the orgin it looks like (but you can use any given point really) and then just follow it, rise 1 and run 2. Rise 2 and run 3 doesn’t work so it has to be 1.2 or (c)
Answer:39798
Step-by-step explanation:hope this helps :)
Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15
a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
=0.005
b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
z=-0.15
thus the value of x will be found as follows:
-0.05=(x-269)/15
-0.05(15)=x-269
-0.75=x-269
x=-0.75+269
x=268.78
The length that separates premature babies from those who are not premature is 268.78 days
Answer:
Step-by-step explanation:
(6,18)
did this answer your question...no. OK well that is your loss
