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Ostrovityanka [42]

3 years ago

6

Hailey’s new puppy, Sparky, weighed 4 pounds at six weeks old. If the puppy gains 2.5 pounds each month, after how many more mon

ths will Sparky weigh 14 pounds? Is this situation modeled by a linear function or an exponential function?

2 answers:

IgorC [24]3 years ago

8 0

Answer:

its A

Step-by-step explanation:

kakasveta [241]3 years ago

3 0

Answer:

It will take 4 months, so when Sparky is 5 1/2 months old they will weigh 14 pounds

Step-by-step explanation:

1. subtract 4 from 14, since parky already weighs 4 pounds

2. divide 10 b 2.5 to get 4 months

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Identify an equation in slope-intercept form for the line parallel to y = -3x + 7

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B

Step-by-step explanation:

B and D are the only ones with the same slope (-3x) which is required for the line to be parallel.

and if you graph it out, you will find that B is the correct answer because it passes through (2,-4).

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zmey [24]

Answer:

Part 1) The inequality that represent this situation is $5(x+7)^{2} \geq1,050$ or $5x^{2}+70x+245 \geq1,050$

Part 2) Yes, 8 inches is a reasonable width for his tablet

Step-by-step explanation:

Part 1)

Let

L -----> the length of the screen television

W ----> the width of the screen television

x ----> the width of Andrew's tablet

we know that

$L=5W$ ------> equation A

$W=x+7$ ----> equation B

The area of the television is

$A=LW$ -----> equation C

Substitute equation A and equation B in equation C

$A=5(x+7)(x+7)$

$A=5(x+7)^{2}$

$5(x+7)^{2} \geq1,050$

$5(x^{2}+14x+49) \geq1,050$

$5x^{2}+70x+245 \geq1,050$ ------> inequality that represent this situation

Part 2) Determine if 8 inches is a reasonable width for his tablet

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Substitute in the inequality

$5(8+7)^{2} \geq1,050$

$5(15)^{2} \geq1,050$

$1,125 \geq1,050$ -----> is true

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3 years ago

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Answer:

Part A) $sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}$

Part B) $tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) $sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}$

Step-by-step explanation:

Part A) Find $sin(\alpha)\ and\ cos(\beta)$

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

so

$sin(\alpha)=cos(\beta)$

Find the value of $sin(\alpha)$ in the right triangle of the figure

$sin(\alpha)=\frac{8}{14}$ ---> opposite side divided by the hypotenuse

simplify

$sin(\alpha)=\frac{4}{7}$

therefore

$sin(\alpha)=\frac{4}{7}$

$cos(\beta)=\frac{4}{7}$

Part B) Find $tan(\alpha)\ and\ cot(\beta)$

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

so

$tan(\alpha)=cot(\beta)$

<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

Let

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$tan(\alpha)=\frac{8}{2\sqrt{33}}$ ---> opposite side divided by the adjacent side angle alpha

simplify

$tan(\alpha)=\frac{4}{\sqrt{33}}$

therefore

$tan(\alpha)=\frac{4}{\sqrt{33}}$

$tan(\beta)=\frac{4}{\sqrt{33}}$

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we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

so

$sec(\alpha)=csc(\beta)$

Find the value of $sec(\alpha)$ in the right triangle of the figure

$sec(\alpha)=\frac{1}{cos(\alpha)}$

Find the value of $cos(\alpha)$

$cos(\alpha)=\frac{2\sqrt{33}}{14}$ ---> adjacent side divided by the hypotenuse

simplify

$cos(\alpha)=\frac{\sqrt{33}}{7}$

therefore

$sec(\alpha)=\frac{7}{\sqrt{33}}$

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