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Yanka [14]
3 years ago
6

Please help me answer the following question.

Mathematics
2 answers:
adelina 88 [10]3 years ago
8 0

Answer:

The answer is D-- 13.3

Step-by-step explanation:

Make it a fraction.  5/6 = x/16.  Cross multiply to get 6x=80.  Divide both sides by 6 to get x=13.333

Fudgin [204]3 years ago
5 0

Answer:

180 - 120 - 25 = 35

i think that is good answer

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2. aubrey solves the equation x-4 = 4 - x and shows her work she found that x = 4 and x = 5 what mistake did she make what is th
Tatiana [17]

Answer: x doesn't equal four x would have to equal -5 because it cant before because it would be a zero and there would be no solution

Step-by-step explanation: brainliest plz

7 0
3 years ago
PLS help me with thisss:((((((​
lara31 [8.8K]

Answer:

C and B

Step-by-step explanation:

(6)

\frac{3x-7y}{8} × \frac{6}{3x-7y} ← cancel 3x - 7y on numerator and denominator

= \frac{1}{8} × \frac{6}{1} = \frac{6}{8} = \frac{3}{4} → C

(7)

\frac{6x}{x^2-9} ÷ \frac{8}{4x-12}

Factorise the denominators of both fractions

x² - 9 = x² - 3² = (x - 3)(x + 3) ← difference of squares

4x - 12 ← factor out 4 from each term

= 4(x - 3)

Then rewrite as

\frac{6x}{(x-3)(x+3)} ÷ \frac{8}{4(x-3)} ← cancel 8 and 4 by 4

= \frac{6x}{(x-3)(x+3)} ÷ \frac{2}{x-3}

• leave first fraction, change ÷ to × , turn second fraction ' upside down'

= \frac{6x}{(x-3)(x+3)} × \frac{x-3}{2} ← cancel x - 3 on numerator and denominator

= \frac{6x}{x+3} × \frac{1}{2} ← cancel 2 and 6 on numerator and denominator

= \frac{3x}{x+3} → B

8 0
3 years ago
Find the measure of x.<br> 40<br> 45°<br> x = [?]<br> Round to the nearest tenth.
MAXImum [283]

L=40×Tan45

=40

x²=root(40²-40²)

=0

3 0
3 years ago
H(x)=5/sqrt(2x+10), find the domain using set builder notation.
marissa [1.9K]

The given expression is

h(x) = \frac{5}{\sqrt{2x+10}}

THe given expression is a rational expression, and rational expression should not have 0 in the denominator.

Moreover, the denominator is a square root term, and square root don't have a value for negative number .

Therefore 2x+10 must be greater then 0. That is

2x+10>0&#10;\\&#10;2x>-10&#10;\\&#10;x>-5

Therefore the required domain in set builder form is

{x | x>-5}

4 0
4 years ago
What is the area of the shaded region ??
alina1380 [7]

Answer:

B  0.6825

Step-by-step explanation:

From the tables

0.80 = 02881 of the area

1.25 = 0.3944 of the area

Sum of these 2 = 0.6825


3 0
3 years ago
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