All categories

3 years ago

Please help me answer the following question.

Mathematics

2 answers:

adelina 88 [10]3 years ago

8 0

Answer:

The answer is D-- 13.3

Step-by-step explanation:

Make it a fraction. 5/6 = x/16. Cross multiply to get 6x=80. Divide both sides by 6 to get x=13.333

Fudgin [204]3 years ago

5 0

Answer:

$180 - 120 - 25 = 35$

i think that is good answer

You might be interested in

1/4 of 24 on tape diagram

Lemur [1.5K]

Draw the tape diagram: a long rectangle and divide it into 4 squares in a row.The whole rectangle represents 24 (as a whole number), you're dividing it into 4 parts because you want to know what is 1/4 of it.Now, to find the value of each square: 24:4 = 6.Put the number 6 in each square, and you have found your result.1/4 of 24 is 6.

8 0

4 years ago

Fill in the missing parts: 5/7 of ... is 1/7 Please help I really don't get it

yaroslaw [1]

Answer:

of in math means multiply so I would assume its asking you to multiply 5/7 and 1/7. that would give you 28/3 which simplified gives you 7.

3 0

3 years ago

Read 2 more answers

Explain the difference in meaning between |-3| and -3

Firlakuza [10]

Absolute value is always positive, so |-3| equals positive 3

8 0

3 years ago

Read 2 more answers

The point, line, and pair of intersecting lines are special types of conic sections. true or false

Bumek [7]

Answer:

True

Step-by-step explanation:

In mathematics, a conic section (or just conic) is a curve obtained by intersecting a cone (more precisely, a right circular conical surface) with a plane. The point line and pair of intersecting lines are special types of conic sections.

4 0

3 years ago

Special right triangles

garik1379 [7]

Answer: The answers are given below.

Step-by-step explanation: The calculations are as follows.

(1) We have in the given right-angled triangle,

$\tan 30^\circ=\dfrac{10}{x}\\\\\Rightarrow \dfrac{1}{\sqrt3}=\dfrac{10}{x}\\\\\Rightarrow x=10\sqrt3,$

and

$y^2=(10)^2+x^2=100+(10\sqrt3)^2=100+300=400\\\\\Rightarrow y=20.$

∴ x = 10√3 and y = 20.

(2) We have in the given right-angled triangle,

$\cos 60^\circ=\dfrac{2}{x}\\\\\Rightarrow \dfrac{1}{2}=\dfrac{2}{x}\\\\\Rightarrow x=4,$

and

$y^2=x^2-2^2=16-4=12\\\\\Rightarrow y=2\sqrt3.$

∴ x = 4 and y = 2√3.

(3) We have in the given right-angled triangle,

$\cos 30^\circ=\dfrac{7}{y}\\\\\Rightarrow \dfrac{\sqrt3}{2}=\dfrac{7}{y}\\\\\Rightarrow y=\dfrac{14\sqrt3}{3},$

and

$\sin 30^\circ=\dfrac{7}{x}\\\\\Rightarrow \dfrac{1}{2}=\dfrac{7}{x}\\\\\Rightarrow x=14.$

∴ x = 14 and y = 14√3.

(4) We have in the given right-angled triangle,

$\sin 30^\circ=\dfrac{x}{6}\\\\\Rightarrow \dfrac{1}{2}=\dfrac{x}{6}\\\\\Rightarrow x=3,$

and

$\cos 30^\circ=\dfrac{y}{6}\\\\\Rightarrow \dfrac{\sqrt3}{2}=\dfrac{y}{6}\\\\\Rightarrow y=3\sqrt3.$

∴ x = 3 and y = 3√3.

(5) We have in the given right-angled triangle,

$\sin 30^\circ=\dfrac{y}{10}\\\\\Rightarrow \dfrac{1}{2}=\dfrac{y}{10}\\\\\Rightarrow y=5,$

and

$\cos 30^\circ=\dfrac{x}{6}\\\\\Rightarrow \dfrac{\sqrt3}{2}=\dfrac{x}{10}\\\\\Rightarrow y=5\sqrt3.$

∴ x = 5 and y = 5√3.

(6) We have in the given right-angled triangle,

$\sin 30^\circ=\dfrac{x}{8}\\\\\Rightarrow \dfrac{1}{2}=\dfrac{x}{8}\\\\\Rightarrow x=4,$

and

$\cos 30^\circ=\dfrac{y}{8}\\\\\Rightarrow \dfrac{\sqrt3}{2}=\dfrac{y}{8}\\\\\Rightarrow y=4\sqrt3.$

∴ x = 4 and y = 4√3.

(7) We have in the given right-angled triangle,

$\cos 30^\circ=\dfrac{7\sqrt3}{y}\\\\\Rightarrow \dfrac{\sqrt3}{2}=\dfrac{7\sqrt3}{y}\\\\\Rightarrow y=14,$

and

$\sin 30^\circ=\dfrac{x}{y}\\\\\Rightarrow \dfrac{1}{2}=\dfrac{x}{14}\\\\\Rightarrow x=7.$

∴ x = 7 and y = 14.

(8) We have in the given right-angled triangle,

$\cos 30^\circ=\dfrac{6\sqrt3}{y}\\\\\Rightarrow \dfrac{\sqrt3}{2}=\dfrac{6\sqrt3}{y}\\\\\Rightarrow y=12$

and

$\sin 30^\circ=\dfrac{x}{y}\\\\\Rightarrow \dfrac{1}{2}=\dfrac{x}{12}\\\\\Rightarrow x=6$

∴ x = 6 and y = 12.

(9) We have in the given right-angled triangle,

$\cos 30^\circ=\dfrac{\sqrt3}{y}\\\\\Rightarrow \dfrac{\sqrt3}{2}=\dfrac{\sqrt3}{y}\\\\\Rightarrow y=2$

and

$\sin 30^\circ=\dfrac{x}{y}\\\\\Rightarrow \dfrac{1}{2}=\dfrac{x}{2}\\\\\Rightarrow x=4.$

∴ x = 4 and y = 2.

Thus, all are completed.

3 0

3 years ago