Hi there!
![\large\boxed{(-\infty, \sqrt[3]{-4}) \text{ and } (0, \infty) }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%28-%5Cinfty%2C%20%5Csqrt%5B3%5D%7B-4%7D%29%20%5Ctext%7B%20and%20%7D%20%280%2C%20%5Cinfty%29%20%7D)
We can find the values of x for which f(x) is decreasing by finding the derivative of f(x):

Taking the derivative gets:

Find the values for which f'(x) < 0 (less than 0, so f(x) decreasing):
0 = -8/x³ - 2
2 = -8/x³
2x³ = -8
x³ = -4
![x = \sqrt[3]{-4}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B-4%7D)
Another critical point is also where the graph has an asymptote (undefined), so at x = 0.
Plug in points into the equation for f'(x) on both sides of each x value to find the intervals for which the graph is less than 0:
f'(1) = -8/1 - 2 = -10 < 0
f'(-1) = -8/(-1) - 2 = 6 > 0
f'(-2) = -8/-8 - 2 = -1 < 0
Thus, the values of x are:
![(-\infty, \sqrt[3]{-4}) \text{ and } (0, \infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%20%5Csqrt%5B3%5D%7B-4%7D%29%20%5Ctext%7B%20and%20%7D%20%280%2C%20%5Cinfty%29)
Answer:
This equation belongs to One variable linear equation because there is one variable = x and the exponent number is one
solving equations :
x= 44 quarts
Answer:
6 cm
Step-by-step explanation:
36-24=12 and 12/2 is 6
Hope this helps!!!!!!!!!!!!!!
There are a few ways to find out the correct answer. One of them is to divide 2.40 by 6 to get a price of one cake and then multiply it by 10:
2.40 ÷ 6 = 0.40
0.40 * 10 = 4.00
Answer: Ten cakes would cost 4 pounds.
Answer:
A
Step-by-step explanation:
first lets find the area of the square
A=l*w
12*12=144 m^2
then lets find the are of the circle
A=pi*r^2
A=3.14*(d/2)^2
the diameter of the circle is 12m
A=3.14*(12/2)^2
A=3.14*(6)^2
A=3.14*36
A=113.04 m^2
Now, lets subtract the area of the circle form the area of the square
144-113.04= 30.96 m^2
So, the answer is A