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3 years ago

Find the height of a cylinder that has a radius of 5 m and a volume of 450 mº.

Mathematics

1 answer:

jekas [21]3 years ago

5 0

The height of cylinder is 5.73 meters.

Further explanation:

Given

$Volume\ of\ cylinder=V=450\ m^3\\Radius=r=5\ m$

The formula for calculating volume of cylinder is:

$V=\pi r^2h$

Putting the values of volume, radius and pi

$450=3.14*(5)*h\\450=3.14*25*h\\450=78.5*h\\h=\frac{450}{78.5}\\h=5.73\ meters$

The height of cylinder is 5.73 meters.

Keywords: Volume of cylinder, Surface area of cylinder

Learn more about volume of cylinder at:

#LearnwithBrainly

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bekas [8.4K]

As it says he keeps 'pairs' of shoes so the answer has to be an even 'number' - ie B, C and E are all possible answers.

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2 years ago

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Claire jogs 6 miles per hour and Megan jogs 5 miles per hour. they start together at their campsite and jog to an outpost 18 mil

horrorfan [7]

Answer:

16.364 miles

Step-by-step explanation:

Speed of Claire = 6 miles per hour

Speed of Megan= 5 miles per hour

Distance from camp site to out post = 18 miles

Time for Claire to travel=18/6= 3 hours

Time for Megan to travel = 18/5 = 3.6 hours

The time they meet will be equal

Claire distance= 18 + x

Megan distance = 18-x

Claire time =( 18+x)/6

Megan Tim =( 18-x)/5

(18+x)/6 =(18-x)/5

5(18+x)= 6(18-x)

90 +5x = 108-6x

11x=18

X=18/11

X=1.636 Miles

So the distance from the Outpost to where they meet = 18-1.636

= 16.364 miles

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3 years ago

What does (x2−50x−600)÷(x−60) equal?

Natalka [10]

Answer:

x+10 x ≠ 60

Step-by-step explanation:

(x^2−50x−600)

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(x−60)

Factor the numerator

(x-60)(x+10)

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(x-60)

Cancel the like terms

x+10

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3 years ago

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klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

$\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}$

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

$CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack$

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

$CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack$

Where (from tables):

$Z_{0.99}=2.33$

Finally, the interval at 98% confidence level is:

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1 year ago

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Fantom [35]

Answer:

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