1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3
Recall that 
, so
ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3
Condense the left side by using sum and difference properties of logarithms:
Then
ln(2/3 <em>x</em> ¹ʹ³) = 3
Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)
exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)
Now exp(ln(<em>x</em>)) = <em>x </em>for all <em>x</em>, so this simplifies to
2/3 <em>x</em> ¹ʹ³ = exp(3)
Now solve for <em>x</em>. Multiply both sides by 3/2 :
3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)
<em>x</em> ¹ʹ³ = 3/2 exp(3)
Raise both sides to the power of 3:
(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³
<em>x</em> = 3³/2³ exp(3×3)
<em>x</em> = 27/8 exp(9)
which is the same as
<em>x</em> = 27/8 <em>e</em> ⁹
Answer:
x is in the range [-1,4]
Step-by-step explanation:
I haven't worked with absolute value inequalities in awhile, but let's take a wack at this.
We are given the following inequality:
| 2x - 3 | <= 5
This implies two possible cases:
[1] -5 <= 2x -3
Or
[2] 2x - 3 <= 5
So let's solve x for both of these cases:
[1] -5 <= 2x - 3
-2 <= 2x
-1 <= x
[2] 2x - 3 <= 5
2x <= 8
x <= 4
So from these cases, we can say the following is true:
x >= -1 and x <= 4
Thus, we can write this in the form
-1 <= x <= 4
Or in interval notation:
{ x is element of reals | -1 <= x <= 4}
Also written as
x is in the range [-1,4]
Where the closed brackets represent 1 and 4 as possible answers whereas parenthesis would imply they were not.
Cheers.
Answer:
Yes.
Step-by-step explanation:
Let's write out each problem:
= 2.3
= 8
Now that we have both answers to each expression, we can tell that , in fact, is larger than the square root of 5.
So your answer is, "Yes, is bigger than the square root of 5.
Feel free to give brainlest.
Have an amazing day!
The tangent of an angle is the ratio of the opposite side to the adjacent side.
... tan(45°) = (height above eye level)/(20 m)
... height above eye level = (20 m)·tan(45°) = (20 m)·1 = 20 m
_____
Eye level is 1.7 m above ground, so the height of the flagpole above ground is
... height of pole = height above eye level + height of eye level
... height of pole = 20 m + 1.7 m = 21.7 m
