Solve. (3x)^2 - 7y^2 when x = 3 and y = 2
2 answers:
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Can't factor
use quadratic
for
ax^2+bx+c=0
x=
given
1x^2-4x+85=0
a=1
b=-4
c=85
x=
x=
x=
x=
remember that √-1=i
x=
x=
x=2+/-9i
x=2+9i or x=2-9i
use quadratic
for
ax^2+bx+c=0
x=
given
1x^2-4x+85=0
a=1
b=-4
c=85
x=
x=
x=
x=
remember that √-1=i
x=
x=
x=2+/-9i
x=2+9i or x=2-9i
Answer:
Step-by-step explanation:
Remember that it doesn't matter how many numbers are after the tenths place of a decimal point what matters is the tenths place itself. If you have a decimal that has dozens of numbers but it's tenth place is a 3 and then you have a decimal with 5 numbers in whole but it's tenths place is 4, the 4 is greater then the 3 simply because it's greater in tenths.
Hope this helps.