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marissa [1.9K]
4 years ago
14

{144} " alt="x {2} = \frac{25}{144} " align="absmiddle" class="latex-formula">
I don't understand at all​
Mathematics
1 answer:
Amanda [17]4 years ago
4 0

Step-by-step explanation:

Hey, there!!

Let me explain you very simply, ok.

Here, according to the question,

{x}^{2} =  \frac{25}{144}

X is square so, which finding the value of x you must take it to the right side (in root form ). so,

x =  \sqrt{ \frac{25}{144} }

Now, as we know that,

sq.root of 25 = 5

sq.root of 144 = 12

Now, you write it as,

x =  \sqrt{ \frac{ {5}^{2} }{ {12}^{2} } }

or \: x =  \sqrt{( { \frac{5}{12} )}^{2} }

Now, square root and (5/12) square ( square root , square gets cancelled).

You will get as,

x =  \frac{5}{12}

And its your simplified answer.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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B

Step-by-step explanation: dilated means get bigger so (0,10) times 3 is (0,30) and (8,6) times 3 is (24,18) and (4,2) times 3 is (12,6)

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4 years ago
- 5/8c = 20 <br> A. -34<br> B. -32<br> C. 32<br> D. 34
lutik1710 [3]
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4 years ago
Suppose the coefficient matrix of a linear system of four equations in four variables has a pivot in each column. Explain why th
Veseljchak [2.6K]

If the coefficient matrix has a pivot in each column, it means that it is shaped like this:

A=\left[\begin{array}{cccc}a_{1,1}&a_{1,2}&a_{1,3}&a_{1,4}\\0&a_{2,2}&a_{2,3}&a_{2,4}\\0&0&a_{3,3}&a_{3,4}\\0&0&0&a_{4,4}\end{array}\right]

So, the correspondant system

Ax = b

will look like this:

\left[\begin{array}{cccc}a_{1,1}&a_{1,2}&a_{1,3}&a_{1,4}\\0&a_{2,2}&a_{2,3}&a_{2,4}\\0&0&a_{3,3}&a_{3,4}\\0&0&0&a_{4,4}\end{array}\right]\cdot \left[\begin{array}{c}x_1\\x_2\\x_3\\x_4\end{array}\right] = \left[\begin{array}{c}b_1\\b_2\\b_3\\b_4\end{array}\right]

This turn into the following system of equations:

\begin{cases}a_{1,1}x_1+a_{1,2}x_2+a_{1,3}x_3+a_{1,4}x_4=b_1\\a_{2,2}x_2+a_{2,3}x_3+a_{2,4}x_4=b_2\\a_{3,3}x_3+a_{3,4}x_4=b_3\\a_{4,4}x_4=b_4\end{cases}

The last equation is solvable for x_4: we easily have

x_4=\dfrac{b_4}{a_{4,4}}

Once the value for x_4 is known, we can solve the third equation for x_3:

x_3 = \dfrac{b_3-a_{3,4}x_4}{a_{3,3}}

(recall that x_4 is now known)

The pattern should be clear: you can use the last equation to solve for x_4. Once it is known, the third equation involves the only variable x_3. Once

4 0
3 years ago
PLEASE HELP ME WILL MARK BRAINLIEST !!! :)
Roman55 [17]

Answer:

lateral area = side area = (10 x 6 x 2) + (14 x 10 x 2) = 400 in²

total surface area = lateral area + top & bottom area = 400 + (14 x 6 x 2) = 568 in²

8 0
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