All categories

3 years ago

HELLPP PLEASE :) THIS IS HARD BRAINLIEST!

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

7 0

Answer:

1).B

2).A

3).D

4).B

5).C

6).D

7).D

8).B

9).C

10). I believe it is A

Step-by-step explanation:

I'm sorry, i do not know how to explain this, I hope I helped you in some way and I hope these answers work for you :)

You might be interested in

PLEASE HELP!!! WILL GIVE FIRST ANSWER BRAINLEST!!!!18 is 1.2% of what number

IRINA_888 [86]

So the right answer is 1500.

look at the attached picture⤴

Hope it will help you..

6 0

3 years ago

Read 2 more answers

Find the distance from the point \left(-8,-3,10\right) to the plane 3 x - 8 y+0 z=-8.

algol13

I dont know i will tell you when i find out

4 0

3 years ago

Read 2 more answers

Diana put $8000 in a 10-year CDpaying 5% interest compoundedmonthly. After 2 years, shewithdrew all her money, and as anearly wi

Svet_ta [14]

Answer:

$8,430.23

Explanation:

From the statement of the problem:

• The principal amount = $8,000

• Interest Rate = 5%

• Compounding Period = 12 (Monthly)

The compound interest formula is given as:

$A(n)=P\left(1+\frac{r}{k}\right)^{nk}$

Using the compound period formula, we first, calculate the amount in her account at the end of 1 year.

$\begin{gathered} A(1)=8000\left(1+\frac{0.05}{12}\right)^{12\times1} \\ A(1)=\$8409.30 \end{gathered}$

This means that the interest she made during the first year is:

$\text{ Interest during the first year}=8409.30-8000=\$409.30$

Next, calculate the amount in her account at the end of the second year.

$\begin{gathered} A(2)=8000\left(1+\frac{0.05}{12}\right)^{12\times2} \\ A(2)=\$8839.53 \end{gathered}$

Since she paid back all the interest she made during the first year, the amount Diana was left with is:

$\begin{gathered} 8839.53-409.30 \\ =8,430.23 \end{gathered}$

Diana was left with $8,430.23.

6 0

1 year ago

Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2.

insens350 [35]

Answer:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

Step-by-step explanation:

Given

$p(x) = \frac{x^2-2x-3}{x+2}$ -- Missing from the question

Required

The behavior of the function around its vertical asymptote at $x = -2$

$p(x) = \frac{x^2-2x-3}{x+2}$

Expand the numerator

$p(x) = \frac{x^2 + x -3x - 3}{x+2}$

Factorize

$p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}$

Factor out x + 1

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

$x -> -2^{-}$ Say x = -3

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

$p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12$

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

$x->-2^{-}, p(x)->-\infty$

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: $x>-2$

Say x = -2.1

$p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1$

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

$x->-2^{+}, p(x)->-\infty$

So, the behavior is:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

6 0

3 years ago

A charitable organization holds a canned food drive to benefit the local food bank. The number of cans collected by the voluntee

kirill115 [55]

Answer:

Step-by-step explanation:

Minimum: 2

Quartile Q1: 4.5

Median: 10

Quartile Q3: 15

Maximum: 19

8 0

2 years ago