Answer:
a. 0.01
b. 0.001
c. The identification field of the packet fragment can be used to uniquely identify and collate the fragments lost in transmission.
Explanation:
The probability of losing a packet is 10% or 0.1, so the probability of losing the packet twice during transmission;
= 0.1 x 0.1 = 0.01
When any fragments have been part of the transmission, the probability of the packet is dependent on the fragments;
= 0.01 x 0.1 = 0.001
The identification field is a unique 16-bit value assigned to an IPv4 packet, when a packet is fragmented for transmission, its field is used to collate the unique fragments in the packet.
Answer:
Explanation:
The following code is written in Java and loops through 10 times. Each time generating 2 random dice rolls. If the sum is 10 it breaks the loop and outputs a "You Win" statement. Otherwise, it outputs "You Lose"
import java.util.Random;
class Brainly {
public static void main(String[] args) {
UseRandom useRandom = new UseRandom();
boolean youWin = false;
for (int x = 0; x<10; x++) {
int num1 = useRandom.getRandom(6);
int num2 = useRandom.getRandom(6);
if ((num1 + num2) == 10) {
System.out.println("Number 1: " + num1);
System.out.println("Number 2: " + num2);
System.out.println("You Win");
youWin = true;
break;
}
}
if (youWin == false) {
System.out.println("You Lose");
}
}
}
class UseRandom{
public int getRandom(int n)
{
Random r=new Random();
int rand=r.nextInt(n);
return rand;
}}
Answer:
answer is D
Explanation:
as the block returns the number of array members, the most likely scenario is the last one.
Gmail is an example of a locally installed email client