Question

Create a game that rolls two dies (number from 1 to 6 on the side) sequentially for 10 times (use loop). If at least once out of 10 times the sum of two random numbers is equal to 10, you win, else you loose. You will need to get your own method getRandom(int n) that generates a random number, see below (you can modify it as needed), a loop, and IF statement in the loop that checks if a sum of two random numbers is 10 or not.
Please start your program as follows, similar to what we did in class:
import java.util.Random;
public class UseRandom{
//your method getRandom() is here below, n is a range for a random number from 0 to n
public int getRandom(int n)
{
Random r=new Random();
int rand=r.nextInt(n);
return rand;
}
//code continues here, don't forget your main() method inside the class, and making your own object in main() using "new" keyword.

Answer 1

Answer:

Explanation:

The following code is written in Java and loops through 10 times. Each time generating 2 random dice rolls. If the sum is 10 it breaks the loop and outputs a "You Win" statement. Otherwise, it outputs "You Lose"

import java.util.Random;

class Brainly {

   public static void main(String[] args) {

       UseRandom useRandom = new UseRandom();

       boolean youWin = false;

       for (int x = 0; x<10; x++) {

           int num1 = useRandom.getRandom(6);

           int num2 = useRandom.getRandom(6);

           if ((num1 + num2) == 10) {

               System.out.println("Number 1: " + num1);

               System.out.println("Number 2: " + num2);

               System.out.println("You Win");

               youWin = true;

               break;

           }

       }

       if (youWin == false) {

           System.out.println("You Lose");

       }

   }

}

class UseRandom{

   public int getRandom(int n)

   {

       Random r=new Random();

       int rand=r.nextInt(n);

       return rand;

   }}