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Vesna [10]
3 years ago
13

Which of the following is the most abstract?

Computers and Technology
2 answers:
densk [106]3 years ago
8 0

Answer:

<em>Hello, I think </em><em>A) Peanut butter and jelly sandwich</em>

<em>Hope That Helps....</em>

marysya [2.9K]3 years ago
4 0

D. The word "food" is the most abstract because it is the least specific and does not specify what food it is exactly.

Hope this helps!! :)

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Which consumer document is most likely to help you if you have trouble figuring out how to operate a device
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The answe is 'B', as it should contain all the required information on how to operate the device, as well as a troubleshooting guide.
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The buttons on a specific tab are organized into logical Ribbons. <br> T<br> F
NeTakaya
I believe the answer would be true
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Read 2 more answers
Write a generator function named count_seq that doesn't take any parameters and generates a sequence that starts like this: 2, 1
-BARSIC- [3]

Answer:

#required generator function

def count_seq():

   #starting with number 2. using string instead of integers for easy manipulation

   n='2'

   #looping indefinitely

   while True:

       #yielding the integer value of current n

       yield int(n)

       #initializing an empty string

       next_value=''

       #looping until n is an empty string

       while len(n)>0:

           #extracting first digit (as char)

           first=n[0]

           #consecutive count of this digit

           count=0

           #looping as long as n is non empty and first digit of n is same as first

           while len(n)>0 and n[0]==first:

               #incrementing count

               count+=1

               #removing first digit from n

               n=n[1:]

           #now appending count and first digit to next_value

           next_value+='{}{}'.format(count,first)

       #replacing n with next_value

       n=next_value

#testing, remove if you don't need this

if __name__ == '__main__':

   #creating a generator from count_seq()

   gen=count_seq()

   #looping for 10 times, printing next value

   for i in range(10):

       print(next(gen))

Explanation:

6 0
3 years ago
Consider a set of mobile computing clients in a certain town who each
poizon [28]

Answer: answer given in the explanation

Explanation:

We have n clients and k-base stations, say each client has to be connected to a base station that is located at a distance say 'r'. now the base stations doesn't have allocation for more than L clients.

To begin, let us produce a network which consists of edges and vertex

Network (N) = (V,E)

where V = [S, cl-l, - - - -  cl-n, bs-l - - - - - - bs-k, t]

given that cl-l, - - - - - cl-n represents nodes for the clients

also we have that bs-l, - - - - - bs-k represents the nodes for base station

Also

E = [ (s, cl-i), (cl-i,bs-j), (bs-j,t)]

(s, cl-i) = have capacity for all cl-i (clients)

(cl-i,bs-j) = have capacity for all cl-i  clients & bs-j (stations)

⇒ using Fond Fulkorson algorithm we  find the max flow in N

⇒ connecting cl-i clients to  bs-j stations

      like (cl-i, bs-j) = 1

   if f(cl-i, bs-j)  = 0

⇒ say any connection were to produce a valid flow, then

if cl-i (clients) connected                f(s,cl-i) = 1 (o otherwise)

if cl-i (clients) connected  to bs-j(stations)   f(cl-i,bs-j) = 1 (o otherwise)

   f(bs-j,t) = no of clients  (cl-i)  connected to bs-j

⇒ on each node, the max flow value (f) is longer than the no of clients that can be connected.

⇒ create the connection between the client and base station i.e. cl-l to base bs-j iff    f(cl-i, bs-j) = 1

⇒ when considering the capacity, we see that any client cannot directly connect to the base stations, and also the base stations cannot handle more than L clients, that is because the load allocated to the base statsion is L.

from this, we say f is the max no of clients (cl-i) that can be connected if we find the max flow, we can thus connect the client to the base stations easily.

cheers i hope this helps

5 0
3 years ago
How to create a comparator generic type in java.
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Answer:

public class Person {

//fields

private int id;

private String name;

private Payment pay;

//constructor

public Person(String name, int id,

int startSal, int startBon){

this.name = name;

this.id = id;

this.pay = new Payment(startSal, startBon);

}

//method get name

public String getName(){

return name;

}

//method get id

public int getId(){

return id;

}

//method get start salary

public int getStartSalary(){

return pay.startSalary;

}

//method get start bonus

public int getStartBonus(){

return pay.startBonus;

}

//inner payment class

private class Payment{

int startSalary;

int startBonus;

public Payment(int sal, int bon){

this.startSalary = sal;

this.startBonus = bon;

8 0
2 years ago
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