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pashok25 [27]
4 years ago
5

What equation do you get when you solve ............. ky-bf=fy/m for y?

Mathematics
1 answer:
Xelga [282]4 years ago
5 0
Idk use scientific val
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The scatter plot shows how the cooking time for a beef roast is related to its weight. Which statement is NOT supported by the t
bija089 [108]

Answer:

the statement that is not supported by the trend in this scatter plot is that each additional pound adds about 1 hour of cooking time. (last option)

3 0
3 years ago
Read 2 more answers
10x + 2 y = 24 <br>-5 x + y = -18​
wlad13 [49]

Answer:

(3,-3)

Step-by-step explanation:

First you divide 2 out of the first equation and it turns into 5x+y=12.

Then you write one on top of the other so you can add them. It looks like:

5x + y = 12

-5x + y = -18

Then you add them together and the 5x's cancel each other out and you are left with 2y = -6

So then you divide both sides by 2 and get y = -3

Then you plug -3 into the second equation because it is simpler and get -5x - 3 = -18

So then you add three to both sides and get -5x = -15

And finally you divide both sides by -5 and get x=3

6 0
4 years ago
Hugh bought some magazines that cost $3.95 each and some books that cost $8.95 each.he spent a total of $47.65. If Hugh bought 3
Nookie1986 [14]
He bought 4 books

Steps:

3.95(3) + 8.95b = 47.65
<span>11.85 + 8.95b = 47.65
</span>
Now just subtract 11.85 from both sides and now the equaton shoud look like this

8.95b = 35.8

Now divide 8.95 from both sides and you get...

b=4

Hope this helps!
7 0
3 years ago
How do I solve this
anastassius [24]
\bf \cfrac{x+2}{x^2+6x-7}    so, that function is "defined", ok, what values of "x" are not in the domain, namely, what values can "x" take on and not make the function "undefined", well,  you know, if we end up with a 0 at the denominator, like   \bf \cfrac{x+2}{0}    then, we'd have an "undefined" expression...so... any values of "x" that make the denominator 0, are not really the ones we want, and thus they'd be excluded from the domain.


so, hmm which are those? let's check, let's set the denominator to 0, and solve for "x".

\bf x^2+6x-7=0\implies (x+7)(x-1)=0\implies x=&#10;\begin{cases}&#10;-7\\&#10;1&#10;\end{cases}&#10;\\\\\\&#10;\textit{let's check, } x=-7\quad \cfrac{(-7)+2}{(-7)^2+6(-7)-7}\implies \cfrac{-5}{49-42-7}\implies \cfrac{-5}{0}&#10;\\\\\\&#10;x=1\quad \cfrac{(1)+2}{(1)^2+6(1)-7}\implies \cfrac{3}{1+6-7}\implies \cfrac{-3}{0}
7 0
4 years ago
6x-8y-5x+3y<br> plz reply ASAP thanks.
DiKsa [7]

You can simplify this expression by grouping like terms in the following manner

(6x-5x)-(8y-3y)

Now it will be easy to simplify this expression.

x-5y

Here is your simplified expression.

Grouping like terms is the most easy method to simplify a given expression.

8 0
3 years ago
Read 2 more answers
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