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Oxana [17]
3 years ago
14

If it is 10:30 am what was 8 hours and 45 minutes ago

Mathematics
1 answer:
Fittoniya [83]3 years ago
6 0
What time was it 20 minutes ago
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Which of the following is the correct value for x
USPshnik [31]
(1) 5 is the answer
7 0
3 years ago
If f(x)=(1/8)(8^x) what is f(3)?<br> A. 1/512<br> B. 1/64<br> C. 512<br> D. 64
cestrela7 [59]
Hi there!

Let's solve this problem step by step!
f(x) =  \frac{1}{8} (8 {}^{x})

To find f(3) we must substitute x = 3 into the formula.
f(3) =  \frac{1}{8} (8 {}^{3} )

Now we use PEMDAS (Parenthesis, exponents, multiply, divide, add, subtract) to find our answer.

Work out the exponents inside the parenthesis first.
f(3) =  \frac{1}{8}  \times 512

And finally multiply.
f(3) =  \frac{1}{8}  \times  \frac{512}{1}  =  \frac{512}{8}  = 64

Hence, the answer is D. 64.
~ Hope this helps you!
4 0
3 years ago
Read 2 more answers
Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
3 years ago
if y varies directly as x, and y is 6 when x is 72, what is the value of y when x is 8? a. 1/9 b. 2/3 c. 54 d. 96
Lapatulllka [165]
The value of y when x is 8 is b. 2/3
8 0
3 years ago
Read 2 more answers
4. Find the value of 8 + 12 + 4 + 6 x 1 + 2. Guys I am doing a test and I need help!!
skelet666 [1.2K]
32 is the correct answer I believe if using PEMDAS method
6 0
3 years ago
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