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svlad2 [7]
4 years ago
9

Simplify (3a3 – 7a2 + a) – (6a3 – 4a2 – 8).

Mathematics
1 answer:
ollegr [7]4 years ago
5 0

Answer:

d. -3a3 – 3a² + a +8

Step-by-step explanation:

Simplify the expression.

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Klio2033 [76]

Answer:

option D.Given and reflexive property.

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What is the mapping rule for a 180 degree rotation about the origin? (x, y)g(–y, x) (x, y)g(–y, –x) (x, y)g(–x, –y) (x, y)g(x, –
il63 [147K]

Answer:

I think it is C but not for sure

Step-by-step explanation:

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3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Brilliant_brown [7]

Answer:

f(x)=\sqrt{x-1} -----> Graph C

f(x)=\sqrt{x} -----> Graph A

f(x)=\sqrt{x}-1 -----> Graph B

f(x)=-\sqrt{x} -----> Graph D

f(x)=-\sqrt{x-1} -----> Graph E

Step-by-step explanation:

we have

case a) f(x)=\sqrt{x-1}

Find the domain

we know that

The radicand must be greater than or equal to zero

so

x-1\geq 0

x\geq 1

The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

The range is the interval ----->  [0,∞)

All real numbers greater than or equal to 0

case b) f(x)=\sqrt{x}

Find the domain

we know that

The radicand must be greater than or equal to zero

so

x\geq 0

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

The range is the interval ----->  [0,∞)

All real numbers greater than or equal to 0

case c) f(x)=\sqrt{x}-1

Find the domain

we know that

The radicand must be greater than or equal to zero

so

x\geq 0

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

The range is the interval ----->  [-1,∞)

All real numbers greater than or equal to -1

case d) f(x)=-\sqrt{x}

Find the domain

we know that

The radicand must be greater than or equal to zero

so

x\geq 0

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

The range is the interval ----->  (-∞,0]

All real numbers less than or equal to 0

case e) f(x)=-\sqrt{x-1}

Find the domain

we know that

The radicand must be greater than or equal to zero

so

x-1\geq 0

x\geq 1

The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

The range is the interval ----->  (-∞,0]

All real numbers less than or equal to 0

5 0
3 years ago
If the domain of a function that is reflected over the x-axis is (1, 5), (2, 1), (-1, -7), what is the range?
Tju [1.3M]

Answer:

A. (1, -5), (2, -1), (-1, 7)

Step-by-step explanation:

Reflecting a function over the x-axis:

When a function is reflected over the x-axis, the x-value stays the same, while y changes the signal, so the transformation rule is:

(x,y) \rightarrow (x,-y)

To find the range:

We apply the transformation to the points in the domain. Thus:

(1,5) \rightarrow (1,-5)

(2,1) \rightarrow (2,-1)

(-1,-7) \rightarrow (-1,-(-7)) = (-1, 7)

Thus the correct answer is given by option a.

6 0
3 years ago
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