I’ll help comment the questions and I’ll answer
F should be -1, 6
E should be -4, 2
D should be -4, 9
Answer:
½ ln 3
Step-by-step explanation:
∫ sec²x / tan x dx
If u = tan x, then du = sec²x dx.
∫ du / u
ln|u| + C
ln|tan x| + C
Evaluate between π/4 and π/3.
ln|tan(π/3)| + C − (ln|tan(π/4)| + C)
ln|√3| + C − ln|1| − C
ln(√3)
½ ln 3
C = 2<span>πr
C = 2 * 3.14 * 5.1
C = 32.028
You can round that to A. 32.03, because if the decimal after 2 is greater than it, then you round it to the number which is higher than it, which is 3. </span>
For the first one the nth term is 9n - 8 so the 10th term is 9x10 - 8 = 90-8 = 82
For the second one the nth term is ⅓n + ⅓ so the 11th term is ⅓x11 +⅓ = 3.9999 = 4
