I believe its possibly zero.
We need to first find a common denominator. This means that we need the 12 and the 3 to be the same number. We can change the 1/3 into 4/12 and see that 9/12 is larger than 4/12.
<u>Answer:</u>
The y-intercept of a line that has a slope of negative 3 and passes through point 0 and -7 is ![y = -3x -7](https://tex.z-dn.net/?f=y%20%3D%20-3x%20-7)
<u>Solution:</u>
Let us assume that the slope is m and the y intercept of the line is b
Hence,
--------- (i)
y intercept means we need to find the value of y when x is 0
Here the line passes through point (0,-7) and slope m = (-3)
Now putting the point (0,-7) in equation (i) we get,
![\Rightarrow -7 = m\times0 +b](https://tex.z-dn.net/?f=%5CRightarrow%20-7%20%3D%20m%5Ctimes0%20%2Bb)
Anything multiplied by 0 is 0,
![\Rightarrow -7 = 0+b](https://tex.z-dn.net/?f=%5CRightarrow%20-7%20%3D%200%2Bb)
![\Rightarrow b = -7](https://tex.z-dn.net/?f=%5CRightarrow%20b%20%3D%20-7)
So, the line will be ![y = -3x -7](https://tex.z-dn.net/?f=y%20%3D%20-3x%20-7)
Answer:
x=−5 or x=−40
Step-by-step explanation:
Step 1: Subtract -200 from both sides.
Step 2: Factor left side of equation.
Step 3: Set factors equal to 0.
HOPE IT HELPS:)
Answer:
A. 6 and 30
B. 8 and 28
Step-by-step explanation:
we know that the area of the three squares must satisfy the Pythagorean Theorem so c² = a² + b²
where
c² is the area of the largest square
a² and b² are the areas of the smaller squares
now.. 36² = a² + b2
The sum of the areas of the smaller squares must be equal to 36
therefore
6 and 30 >>>> could be the areas of the smaller squares (6 + 30 = 36)
8 and 28 >>>> could be the areas of the smaller squares (8 + 28 = 36)
hope it clears your mind.
Please mark as the brainliest