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marishachu [46]
3 years ago
11

I don’t know how to do this

Mathematics
1 answer:
zalisa [80]3 years ago
7 0

Answer:

½÷3=0.17

if you're talking about the app, i don't get too

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I don’t get this help thx
juin [17]
6.5693%
I’m not sure what you need to round this up to but this is the furthest I got with it. :)
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10X10 in exponent form?
denpristay [2]

Answer:

{10}^{2}

Step-by-step explanation:

6 0
4 years ago
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Simplify and plz show work on a piece of paper
IrinaK [193]
●) -2 (3a - 4b)-6a + 3b
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3 0
3 years ago
A type of long-range radio transmits data across the Atlantic Ocean. The number of errors in the transmission during any given a
Marianna [84]

Answer:

32.33% probability of having at least 3 erros in an hour.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The mean number of errors is 2 per hour.

This means that \mu = 2

(a) What is the probability of having at least 3 errors in an hour?

Either you have 2 or less errors in an hour, or we have at least 3 errors. The sum of the probabilities of these events is decimal 1. So

P(X \leq 2) + P(X \geq 3) = 1

We want P(X \geq 3)

So

P(X \geq 3) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-2}*(2)^{0}}{(0)!} = 0.1353

P(X = 1) = \frac{e^{-2}*(2)^{1}}{(1)!} = 0.2707

P(X = 2) = \frac{e^{-2}*(2)^{2}}{(2)!} = 0.2707

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.1353 + 0.2707 + 0.2707 = 0.6767

P(X \geq 3) = 1 - P(X \leq 2) = 1 - 0.6767 = 0.3233

32.33% probability of having at least 3 erros in an hour.

6 0
3 years ago
HELP PLEASE DUE IN 3 MINUTES
Morgarella [4.7K]

Answer: it is d becaues that is the mode

4 0
3 years ago
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