The given expression, 81a^6 - 100, is a difference of two squares. The first term 81a^6 is a square of 9a³. The second term, 100, is a square of 10. The factors of the given expression is therefore, (9a³ - 10) x (9a³ + 10).
Answer:
B. (1/2, 3)
Step-by-step explanation:
It is perhaps easiest to try the point values in the equations.
A — 4·2+1 = 9; -2·2 +4 ≠9 . . . . not the answer
B — 4·1/2 +1 = 3; -2·(1/2) +4 = 3 . . . . this is the answer
we need go no further since we have the answer
Answer:
for one its 14x+18
for two its -11x-21
for three its x=12
for four its x=-12
for five x=11/7
Step-by-step explanation:
i hope this helps u
btw like i can see your school in the taskbar so next time just crop that out lol
Sub a =3 and b = 5 into the expression above you get:
8*3+6(2*5-7)
then use bedmas accordingly (this is the order of arithmetic operations)
8*3+6(2*5-7)
=24+6(10-7)
=24+6(3)
=24+18
=42
I believe the answer is ]2 \frac{39}{50}
