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romanna [79]
3 years ago
15

Can someone Help me please

Mathematics
1 answer:
Inessa05 [86]3 years ago
4 0

Answer:

the perimeter is 82 in.

Step-by-step explanation:

add all sides

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Find the volume of a pyramid with a square base, where the perimeter of the base is 8.6 cm and the height of the pyramid is 8.1
Ymorist [56]

Answer:  12.5 CC

Step-by-step explanation:

V=1/3Bh where B is the area of the base and h is the height

The perimeter of the square base is 8.6 so each side is 2.15 and the area of the base is (2.15)^2 or 4.6225

V=1/3(4.6225)(8.1)=12.5cc

4 0
3 years ago
Ana has won a lottery. She was offered two options to receive the award: She can either take it in five installments of $60,000
AleksandrR [38]

Answer:

Results are below.

Step-by-step explanation:

Giving the following information:

She can either take it in five installments of $60,000 annually, starting from now; or she can take a lump-sum of $255,000 now.

<u>First, we determine the value of the 5 installments using a 5% annual compounded rate.</u>

We calculate the future value, and then the present value:

FV= {A*[(1+i)^n-1]}/i

A= annual payments

FV= {60,000*[(1.05^5) - 1]} / 0.05

FV= $331.537.88

PV= FV/(1+i)^n

PV= $259,768.60

At an annual rate of 5% compounded annually, she should choose the five installments instead of the $255,000.

<u>Now, if the annual rate is 6% continuously compounded.</u>

<u>First, we need to calculate the effective interest rate:</u>

r= e^i - 1

r= effective inerest rate

r= e^0.06 - 1

r= 0.0618

FV= {60,000*[(1.0618^5) - 1]} / 0.0618

FV= 339,443.23

PV= 339,443.23/1.0618^5

PV= $251,509.01

At an annual rate of 6% compounded continuously, she should choose the $255,000.

5 0
3 years ago
Write the equation which represents the following transformations
Lady_Fox [76]

Answer:

1234588765

Step-by-step explanation:

5 0
3 years ago
Answer Question number 5 <br> Plzzzzzz
loris [4]

Answer:

Step-by-step explanation:

a = -4/3

d= -1 +4/3 =1/3

last term = 4 1/3 = 13/3

nth term = a +(n-1)d

\frac{-4}{3}+(n-1)*\frac{1}{3}=\frac{13}{3}\\\\(n-1)*\frac{1}{3}=\frac{13}{3}-\frac{-4}{3}\\\\(n-1)*\frac{1}{3}=\frac{13+4}{3}\\\\(n-1)*\frac{1}{3}=\frac{17}{3}\\\\n-1=\frac{17}{3}*\frac{3}{1}\\\\n-1=17\\\\n=17+1=18

Middle terms are 9the term and 10th term

t_{9}=\frac{-4}{3}+8*\frac{1}{3}=\frac{-4}{3}+\frac{8}{3}=\frac{4}{3}\\\\t_{10}=\frac{-4}{3}+9*\frac{1}{3}=\frac{-4}{3}+\frac{9}{3}=\frac{5}{3}\\\\ t_{9}+t_{10}=\frac{4}{3}+\frac{5}{3}=\frac{9}{3}=3\\\\t_{9}+t_{10}=3

3 0
3 years ago
Please help me! i dont know what to do... And my weekend depends on you
ludmilkaskok [199]
2) 5.3
3) -6
4) -6
5) 6
7 0
3 years ago
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