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Eduardwww [97]
3 years ago
9

Your bowl contains 8 red balls, and 9 blue balls, and you draw 4 balls. in how many ways can the selection be made so that at le

ast one of each color is drawn?
Mathematics
1 answer:
kumpel [21]3 years ago
5 0
<span>Your bowl contains 8 red balls, and 9 blue balls, and you draw 4 balls. in how many ways can the selection be made so that at least one of each color is drawn.</span>
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Point F is at (0, -10) and point H is at (-6, 5). Find the coordinates of point G on line segment FH such that the ratio of FG t
Tanya [424]

Answer:

G(x,y)=(-4,0)

Step-by-step explanation:

We use the section formula:

(x,y)=\left(\dfrac{mx_2+nx_1}{m+n}, \dfrac{my_2+ny_1}{m+n}\right)

Given:

F(x_1,y_1)=(0, -10)\\H(x_2,y_2)=(-6, 5)\\FG:GH=m:n=2:1

We substitute the values to get:

G(x,y)=\left(\dfrac{2*-6+1*0}{2+1}, \dfrac{2*5+1*-10}{2+1}\right)\\=\left(\dfrac{-12}{3}, \dfrac{10-10}{3}\right)\\=\left(\dfrac{-12}{3}, \dfrac{0}{3}\right)\\\\G(x,y)=(-4,0)

5 0
4 years ago
-2x + 8 = 18 please help. What does x equal
kakasveta [241]

Answer:

x = -5

Step-by-step explanation:

Step 1: Write equation

-2x + 8 = 18

Step 2: Solve for <em>x</em>

  1. Subtract 8 on both sides: -2x = 10
  2. Divide both sides by -2: x = -5

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

-2(-5) + 8 = 18

10 + 8 = 18

18 = 18

6 0
3 years ago
Read 2 more answers
Is y=3x-5 and 6x=2y+10 a solution
iVinArrow [24]
Y=3x-5
y-3x=-5
Times 2 from both side
y(2)-3x(2)=-5(2)
2y-6x=-10
Times negative from both side
(-)2y-6x(-)=(-)-10
-2y+6x=10
or
6x-2y=10


6x=2y+10
6x-2y=10
Furthermore, we see that both equation have the same 6x-2y=10 which means that both of them have infinity solutions, not a solution. Hope it help!
5 0
3 years ago
Can someone please help me on this question?
Anettt [7]
Whoever sees this have a great day ❤️
5 0
3 years ago
WARNING : NON SENSE ANSWER REPORT TO MODERATOR ​
Rzqust [24]

Answer:

\frac{180}{147}

Step-by-step explanation:

  • Simplify (\frac{3}{-7} - \frac{11}{21} )

=> \frac{(-3 \times 3) - 11}{21}

=> \frac{-9 - 11}{21}

=> \frac{-20}{21}

  • Find the additive inverse of  \frac{-20}{21} by using its property - <em>"Sum of a number & its additive inverse is always zero". </em>Assume that 'x' is an additive inverse of  \frac{-20}{21}.

=> x + \frac{-20}{21} = 0

=> x = 0 - (-\frac{20}{21}) = \frac{20}{21}

  • Simplify (\frac{9}{5} \div \frac{7}{5} )

=> \frac{9}{5} \times \frac{1}{\frac{7}{5} }

=> \frac{9}{5} \times \frac{5}{7}

=> \frac{9}{7}

  • Now, find the product of \frac{9}{7} & \frac{20}{21}

=> \frac{9}{7} \times \frac{20}{21}

=> \frac{180}{147}

3 0
3 years ago
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