Answer:
Following are the solution to the given points:
Step-by-step explanation:
In point 1:
The Reflexive closure:
Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is
Thus, the reflexive closure:
In point 2:
The Symmetric closure:
R relation symmetrically closes by adding(b,a) to R for each (a,b) of R Therefore, here (b,a) is:
Thus, the Symmetrical closure:
Answer:
There is a 0.13% probability that the random sample of 100 nontraditional students have a mean GPA greater than 3.65.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
For this problem, we have that:
Based on the study results, we can assume the population mean and standard deviation for the GPA of nontraditional students is and
.
We have a sample of 100 students, so we need to find the standard deviation of the sample, to use in the place of in the z score formula.
.
What is the probability that the random sample of 100 nontraditional students have a mean GPA greater than 3.65?
This is 1 subtracted by the pvalue of Z when . So
A zscore of 3 has a pvalue of 0.9987.
So, there is a 1-0.9987 = 0.0013 = 0.13% probability that the random sample of 100 nontraditional students have a mean GPA greater than 3.65.
