Combine the like terms to an equivalent expression 4q+3+2q-1=
2 answers:
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After 22 s, the car has velocity
In this time, it will have traveled a distance of
Over the next 29 s, the car moves at a constant velocity of 36.4 m/s, so that it covers a distance of
so that after the first 51 s, the car will have moved 1467 m.
After the 29 s interval of constant speed, the car's negative acceleration kicks in, so that its velocity at time is
The car comes to rest when :
That is, it comes to rest about 6.3 s after the first 51 s. In this interval, it will have traveled
so that after 57.3 s, the total distance traveled by the car is 1581.2 m, or about 1.6 km.