We know that the formula for calculating distance is:
distance d = velocity v * time t
Calculating for each interval:
1: 25 km/hr for 4 minutes
d1 = (25 km / 60 min) (4 min) = 1.67 km
2: 50 km/hr for 8 minutes
d2 = (50 km / 60 min) (8 min) = 6.67 km
3: 20 km/hr for 2 minutes
d2 = (20 km / 60 min) (2 min) = 0.67 km
The total distance covered is:
d = d1 + d2 + d3
d = 1.67 + 6.67 + 0.67
d = 9 km
The average speed is:
s = 9 km (1000 m / km) / (14 min * 60 s / min)
s = 10.72 m / s
<span>y=-11x-8
11x + y = -8 ...this is standard form
hope it helps</span>
Answer:
82.79MPa
Step-by-step explanation:
Minimum yield strength for AISI 1040 cold drawn steel as obtained from literature, Sᵧ = 490 MPa
Given, outer radius, r₀ = 25mm = 0.025m, thickness = 6mm = 0.006m, internal radius, rᵢ = 19mm = 0.019m,
Largest allowable stress = 0.8(-490) = -392 MPa (minus sign because of compressive nature of the stress)
The tangential stress, σₜ = - ((r₀²p₀)/(r₀² - rᵢ²))(1 + (rᵢ²/r²))
But the maximum tangential stress will occur on the internal diameter of the tube, where r = rᵢ
σₜₘₐₓ = -2(r₀²p₀)/(r₀² - rᵢ²)
p₀ = - σₜₘₐₓ(r₀² - rᵢ²)/2(r₀²) = -392(0.025² - 0.019²)/2(0.025²) = 82.79 MPa.
Hope this helps!!
Some points are (7,3) and (-7,-5).
Answer:
NOt finished
Step-by-step explanation:
PAGE 1
1.) enlargement b/c the number is more that 1
2.) reduction b/c the number is less than 1
3.) enlargement b/c the number is more than 1
4.) reduction b/c the number is less than 1
5.) reduction k = 1/3
6.) enlargement k = 5/2 or 2.5
PAGE 2
7.) reduction k = 1/3
8.) enlargement k = 2
PAGE 3
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PAGE 5
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I WILL DO THE SCREENSHOTS TOMORROW
