What is the y-intercept of the line?

Harrizon [31]

Solution for what is 147.1% of 155

155/x=100/147.1
(155/x)*x=(100/147.1)*x - we multiply both sides of the equation by x
155=0.67980965329708*x - we divide both sides of the equation by (0.67980965329708) to get x
155/0.67980965329708=x
228.005=x
x=228.005

now we have:
147.1% of 155=228.005

3 0

3 years ago

Rearrange the formula A = <br> Θr2<br> 2<br> for Θ.

Lina20 [59]

Answer:

$\theta=\frac{2A}{r^2}$

Step-by-step explanation:

Given : The formula $A=\frac{\theta r^2}{2}$

We have to rearrange the given formula for $\theta$

Consider the given formula $A=\frac{\theta r^2}{2}$

Multiply both side by 2, we have,

$2A={\theta r^2$

Divide both side by $r^2$ , we have,

$\frac{2A}{r^2}= \frac{\theta r^2}{r^2}$

Simplify, we get,

$\frac{2A}{r^2}=\theta$

Thus, $\theta=\frac{2A}{r^2}$

3 0

3 years ago

Read 2 more answers

5. A bag contains 5 blue marbles, 4 yellow marbles and 1 red marble. What 1 point

Reptile [31]

Answer:

()

Step-by-step explanation:

Use nCr to figure this out, plug in the numbers and probabilities and solve

5 0

3 years ago

Read 2 more answers

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

3 years ago

Find the sum of the geometric series 40 + 40(1.005) + 40(1.005)^2 + ⋯ + 40(1.005)^11.

KiRa [710]

Answer:

The sum is 493.4

Step-by-step explanation:

In order to find the value of the sum, you have to apply the geometric series formula, which is:

$\sum_{i=1}^{n} ar^{i-1} = \frac{a(1-r^{n})}{1-r}$

where i is the starting point, n is the number of terms, a is the first term and r is the common ratio.

The finite geometric series converges to the expression in the right side of the equation. Therefore, you don't need to calculate all the terms. You can use the expression directly.

In this case:

a=40

b= 1.005

n=12 (because the first term is 40 and the last term is 40(1.005)^11 )

Replacing in the formula:

$\frac{a(1-r^{n})}{1-r} = \frac{40(1-1.005^{12})}{1-1.005}$

Solving it:

The sum is 493.4

4 0

3 years ago