(x+y-3)(x+y+3) = x^2+xy+3x+xy+y^2+3y-3x-3y-9 = -9+x^2+y^2+2xy
Answer:
yes
Step-by-step explanation:
There would be a 1 in 28,561 probability that all 4 horses would place 1st, 2nd, 3rd, and 4th.
According to given angles ,
Angle C=180- angle F (Linear pairs or st.line )
=70
Angle B = 180 - angle B (Same as above)
=80
Now
Angle D =Angle C + Angle B (Exterior angle property of a triangle)
=150°
Enjoy