Answer:
72
Step-by-step explanation:
You can find ten percent of 180 pretty easily, it is 18 (divide by 10) then multiply by 4 to get 40%.
The graph of g(x) is shifted 4 units up ⇒ answer a
Step-by-step explanation:
Let us revise the translation
- If the function f(x) translated horizontally to the right by h units, then its image is g(x) = f(x - h)
- If the function f(x) translated horizontally to the left by h units, then its image is g(x) = f(x + h)
- If the function f(x) translated vertically up by k units, then its image is g(x) = f(x) + k
- If the function f(x) translated vertically down by k units, then its image is g(x) = f(x) - k
∵ The parent function f(x) = x
∵ g (x) = x + 4
- Substitute x in g(x) by f(x)
∴ g(x) = f(x) + 4
- g(x) is f(x) add by 4
- by using the rule of translation above
∵ g(x) = f(x) + k
∵ k = 4
∴ g(x) is the image of f(x) after translation 4 units up
∴ The graph of g(x) is 4 units above the graph of f(x)
The graph of g(x) is shifted 4 units up
Learn more:
You can learn more about translation in brainly.com/question/2451812
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Answer is A, Three months, 1/4
Answer:
1. (-20/3)+[(2×3+2)/3]=-12/3=4
2. (-5/3)-(2/3)-3= -5-2-6=-3
Complete question:
Consider 3 boxes, each of which contains 4 balls in particular, box 1 contains 4 white balls, box 2 contains 3 white balls and 1 red ball, box 3 contains 2 white balls and 2 red balls. Frank chooses a box at random. If boxes 1 and 3 are chosen, Frank extracts 2 balls without replacement. If box 2 is chosen Frank extracts 2 balls with replacement. USE ONLY THE CONDITIONAL PROBABILITY FORMALISM and derive an expression for the probability that the 2 extracted balls are red.
Answer:
11/288
Step-by-step explanation:
We are given:
Box 1: ( 4White, ORed)
Box 2: (3White, 1Red)
Box 3: (2White, 2 Red)
We are told that if Frank choose from Box 1 and Box 3, 2 balls are extracted without replacement.
Since there is no red ball in Box 1, there is no way 2 red balls will come out from Box1.
Our Event, E = getting 2 red balls.
Now Box 1 is ruled out, we have:
P[E(B1)]= 0
P[E/B3)] = (2 2) / (4 2)
= 1/6
If box 2 is chosen, 2 balls are extracted with replacement. Therefore for Box 2:
P(E/B2) = (1/4) *(1/4)
= 1/16
Therefore probability that 2 balls extracted are red, we have:
P(E)=P(E/B1) P(B1) + P(E/B2) P(B2)+P(E/B3) P(B3)

= 11/288