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2 years ago

if rhombus ABCD were reflected across the x axis to create rhombus A'B'C'D', what would the measure of angle D' be?

Mathematics

1 answer:

Mrac [35]2 years ago

8 0

Answer:

D.64

Step-by-step explanation:

A linear line equals up to 180

A+D=180

Substitute 116 for A

116+D=180

Subtract 116 from both sides

D=64

A reflection across the x-axis won't change the measure of an angle

The answer is 64.

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3 years ago

Three friends decide to evenly split their bill at a restaurant. The total bill is $84.99 and they will have to pay an additiona

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Given : The Total Bill at the Restaurant is $84.99

Given : The Additional Tax is $5.10

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3 years ago

If csc ( x ) = 4, for 90 ∘ < x < 180, then sin ( x 2 ) = ? cos ( x 2 ) = ? tan ( x 2 ) = ?

svetlana [45]

Answer:

I'm assuming where you wrote x2, you meant 2x.

Anyway, if csc (x) = 2, since csc(x) = 1/sin(x), we know that 1/sin x = 2, so sin (x) = 1/2. Since sin2x + cos2x = 1, cos2x = 1 - sin2x, so cos x = √1 - sin2x. In this case, cos x = √ 1 - (1/2)2 = √(3/4) = (√3)/2. Finally, since sin x = opp / hyp , cos = adj/ hyp: sin x / cos x = (opp/hyp)/(adj/hyp) = opp/adj = tan x. So this means that tan x = sin x / cos x = 1/2 / √ 3 / 2 = 1/√3 = √3 / 3

At this point, all that is necessary is to use the double angle formulas for sin, cos, and tan.

sin (2x) = 2 sin x cos x = 2 (1/2) (√3/2) = √3 / 2

cos (2x) = cos2x - sin2x = (√3/2)2 - (1/2)2 = 3/4 - 1/4 = 1/2

tan (2x) = 2 tan x / (1 - tan2x) = 2 (√3 / 3) / ( 1 - (√3/3)2) = 2/√3 / (1 - 1/3) = 2/√3 / (2/3) = 3/√3 = √3

To sum up, sin (2x) = √4 / 2, cos (2x) = 1/2, and tan(2x) = ✓3.

Step-by-step explanation:

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2 years ago

Help me please, Calculate the external perimeter of the picture frame:

Studentka2010 [4]

Perimeter of a parallelogram = 2(l+b)
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3 years ago

if rhombus ABCD were reflected across the x axis to create rhombus A'B'C'D', what would the measure of angle D' be?​

if rhombus ABCD were reflected across the x axis to create rhombus A'B'C'D', what would the measure of angle D' be?