Ask question

Ask question

All categories

3 years ago

10

Find the area of a circle with a radius of 8. Either enter an exact answer in terms of π or use 3.14 for π and enter your answer

as a decimal.

1 answer:

Sedbober [7]3 years ago

8 0

Answer:

64π units²

Step-by-step explanation:

The area (A) of a circle is calculated as

A = πr² ( r is the radius )

= π × 8²

= 64π units²

You might be interested in

Can somebody explain to me how to do problem 1?

Brut [27]

Answer:

Two spaces left

Step-by-step explanation:

Basically, you have to plot the points on the graph. The first number in the brackets is the x value and the other one is the y value. You would plot -2 on the x-axis. Since the other value is 0, you have to move left two spaces.

3 0

3 years ago

If its £18.75 per square metre of clear plastic how much will it cost to cover 2x notice boards 1 metre high and 1 metre wide ?

xenn [34]

Just double 18.75 because the total area needed to cover is 2 square meters

3 0

3 years ago

Slope of 2/3 and x-intercept of -3

Vilka [71]

Answer:

$\frac{2}{3}$ ,-3

Step-by-step explanation:

7 0

3 years ago

Explain in words how to find the product of -4(-1.5) using a number line. where do you end up?

Inessa [10]

You end up at positive six

6 0

4 years ago

A process is normally distributed with a mean of 104 rotations per minute and a standard deviation of 8.2 rotations per minute.

Ilia_Sergeevich [38]

Answer:

Option B) In control as this one data point is not more than three standard deviations from the mean

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 104 rotations per minute

Standard Deviation, σ = 8.2 rotations per

We are given that the distribution of process is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

For x = 118

$z = \displaystyle\frac{118-104}{8.2} = 1.7073$

Thus, we could say that this data point lies within three standard deviations from the mean as:

$\mu - 3\sigma < x < \mu + 3\sigma\\104-3(8.2) < x < 104 + 3(8.2)\\79.4 < 118 < 128.6$

Thus, it could be said

Option B) In control as this one data point is not more than three standard deviations from the mean

6 0

4 years ago