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Gennadij [26K]
3 years ago
10

How many times were 12 go into 80

Mathematics
2 answers:
swat323 years ago
8 0
12 goes into 80 ''6'' times with a remainder of 8
Alona [7]3 years ago
6 0
12 goes into 80 7 times = 72 and  you have 8 left over!
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Find EF and FD.
vichka [17]

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Answer:

  EF = 13.1

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Step-by-step explanation:

The distance between two points on a number line is the positive difference between their coordinates.

EF = F - E = 19 -5.9

EF = 13.1

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FD = F - D = 19 -(-16.3) = 19 +16.3

FD = 35.3

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2 years ago
Ericka is also in Mr. Whittaker’s science class and she recorded the variation in water level at a different part of the river.
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Step-by-step explanation:

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4 0
3 years ago
1.) Use the following information to solve the questions. Kay sold 200
Yakvenalex [24]

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Answer:

  • 75 adult tickets
  • 125 child tickets

Step-by-step explanation:

Let 'a' represent the number of adult tickets sold. Then (200-a) is the number of child tickets sold, and the revenue is ...

  8a +5(200 -a) = 1225

  3a = 225 . . . . . . . . . . subtract 1000, simplify

  a = 75 . . . . . . . . . . . . .divide by 3

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75 adult ($8) and 125 child ($5) tickets were sold.

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<em>Additional comment</em>

The question asked here is "how many tickets did Kay sell?" The second line of your problem statement tells you the answer: "Kay sold 200 tickets ...". We have assumed that you are interested in the breakdown of tickets sold, even though that is not the question that is asked here.

3 0
3 years ago
An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can
serg [7]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by:

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0         ......[1]

the solution for the equation is given by:

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

On comparing the given equation with [1] we have;  

a = -16 ,b = 80 and c = 300

then;

t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}

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Simplify:

t = -\frac{5}{2} = -2.5 sec and t = \frac{15}{2} = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec

8 0
3 years ago
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