Simplify the expression (-x)^5(4x)^2?<br>A)-16x^7<br>B)-16x^10<br>C)-8x^7<br>D)16x^10

A store regularly sells t-shirts for $12. during a sale, the shirts are discounted by 15%. what is the price of a t-shirt during

Bumek [7]

$12*85%(the amount of the regular price that you pay)= <span>10.20 </span>

5 0

4 years ago

Help with questions, I don't care if you google it

frutty [35]

Question 1:

$7.488*10^{-8}$ ÷ $3.12*10^{2}$

= $\frac{7.488*10^{-8}}{3.12*10^{2}} = 2.4* 10^{-8-2} = 2.4* 10^{-10}$

Hence, the answer is A.

Question 2:

Mass = $2.8* 10^{-11}$ grams

New mass = $2.8 * 10^{-8}$ milligrams

Question 3:

$2.085*10^{6} = 2,085,000$

Hence, the answer is C.

3 0

3 years ago

1

NikAS [45]

9514 1404 393

Answer:

1.0 N

Step-by-step explanation:

When the length increases by the factor 120/80 = 3/2, the force required is multiplied by the inverse of this: 2/3.

The required force is ...

(2/3)(1.5 N) = 1.0 N

5 0

3 years ago

Easy Sample Ap graphing 50pts! (Easy points!!) (ASAP) (URGENT) (Please check my other questions) Please

snow_lady [41]

Answer:

a) See attachment 1.

b) t² and D

c) See attachment 2.

d) g = 9.8 m/s² (1 d.p.)

Step-by-step explanation:

See attachment 1. The line of best fit is shown in red.

The quantities the student should graph in order to produce a <u>linear relationship</u> between the two quantities are t² and D.

Make a table of values of t² and D:

$\begin{array}{|l|l|l|l|l|l|}\cline{1-6} \rm t^2& 0.0196& 0.1024& 0.2116 & 0.3481& 0.3969\\\cline{1-6} \rm D & 0.10 & 0.50& 1.00 & 1.70 & 2.00\\\cline{1-6}\end{array}$

<u>Plot</u> a graph of D against t² and draw a line of best fit (see attachment 2).

From inspection of the graph, the line of best fit passes through the origin (0, 0) and (0.1024, 5.0). Therefore, use these two points to find the slope of the line:

$\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0.5-0}{0.1024-0}=4.8828125...\:\rm m/s^2$