What is 950% as a fraction

A planet has a circular orbit around a star. It is a distance of 65,000,000 km from the centre of the star. It orbits at an aver

guapka [62]

Answer:

Step-by-step explanation:

Orbit = 2*pi * r

r = 65000000 km

Orbit = 65000000 * 2 * 3.14

Orbit = 406 200 000 km

d = 406 200 000

s = speed = 65000 km / hr

t = time = d / s

t = 406,000,000 / 65000

t = 6280 hours.

1 day = 24 hours.

t = 6280 / 24 = 261.67 days

8 0

3 years ago

Angle Relationships

KonstantinChe [14]

Answer:

D. 21 m

Step-by-step explanation:

I calculated it logically

8 0

3 years ago

Need help with this question!

Katyanochek1 [597]

Answer:

A = 0.85(b +47)
$143.65

Step-by-step explanation:

Since the number of bagels sold already is 47, the total number of bagels sold will be b+47. The revenue from each sale is $0.85, so the total revenue will be ...

A = 0.85·(b +47)

This equation can be written in different forms, but this satisfies the requirement for "an equation."

__

Since b is the number of addition bagels, when 122 additional bagels are sold, the value of b is 122. Then the equation becomes ...

A = 0.85·(122 +47)

A = 0.85·169 = 143.65

Revenue will be $143.65 when 122 additional bagels are sold.

4 0

3 years ago

SAT scores are normed so that, in any year, the mean of the verbal or math test should be 500 and the standard deviation 100. as

vovangra [49]

Answer:

a) $P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)$

$P(Z>1.25)=1-P(Z$

b) $P(400$

$P(-1$

c) $z=-0.842$

And if we solve for a we got

$a=500 -0.842*100=415.8$

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the SAT scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(500,100)$

Where $\mu=500$ and $\sigma=100$

We are interested on this probability

$P(X>625)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)$

And we can find this probability using the complement rule and with the normal standard table or excel:

$P(Z>1.25)=1-P(Z$

Part b

We are interested on this probability

$P(400$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(400$

And we can find this probability with this difference:

$P(-1$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(-1$

Part c

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.8$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.2 of the area on the left and 0.8 of the area on the right it's z=-0.842. On this case P(Z<-0.842)=0.2 and P(Z>-0.842)=0.8

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=-0.842$

And if we solve for a we got

$a=500 -0.842*100=415.8$

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.

8 0

3 years ago

alex won first place in the shot-put with a heave of 35 feet 4 inches. Griffin won second place with a heave of 32 feet 9 inches

Alex Ar [27]

Alex defeated Griffin by 2 feet and 5 inches. 2.5
How to solve: 35.4 - 32.9 = 2.5 :))

6 0

3 years ago