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andre [41]
3 years ago
15

What is 950% as a fraction

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
3 0

Answer:

9 1/2

Step-by-step explanation:

\frac{950}{100}=9\frac{50}{100} = 9 \frac{1}{2}

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0.667 in simple fraction​
lana66690 [7]

Answer:

667/1000

Step-by-step explanation:

3 0
4 years ago
Delta makes 12-volt car batteries. These batteries are known to be normally
blondinia [14]

Answer:

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = 0.5188

The percentage of that Delta car batteries last between three and four years

P(3≤X≤4) = 52%

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the sample size n =12 -volt car batteries</em>

<em>Let  'X' be a Random variable in a normal distribution</em>

<em>Given that mean of the normal distribution = 45 months</em>

<em>Given that the Standard deviation of the normal distribution = 8months</em>

<u><em>Step(ii):-</em></u>

Let  X₁ = 3 years = 12 × 3 = 36 months

Z_{1} = \frac{x_{1} -mean}{S.D} = \frac{36-45}{8} = -1.125

Let X₂ = 4 years  = 12 × 4 = 48 months

Z_{2} = \frac{x_{2} -mean}{S.D} = \frac{48-45}{8} = 0.375

<u><em>Step(iii)</em></u>:-

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = P(-1.125≤Z≤0.375)

                   = P(Z≤0.375) - P(Z≤-1.125)

                   = 0.5 +A(0.375) - (0.5-A(1.125)

                   = 0.5 + 0.1480 - (0.5 -0.3708)

                  = 0.1480 + 0.3708

                 = 0.5188

<u><em>Final answer:-</em></u>

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = 0.5188

The percentage of that Delta car batteries last between three and four years

P(3≤X≤4) = 52%

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5 0
3 years ago
Suppose A and B are independent events. If P(A)=0.2 and P(B)=0.6, what is P(A^B)?
lawyer [7]
OK so you want the probabilty of A and B occurring.  Independet event probabilities are multiplied so its 0.2 * 0.6 = 0.12

b
3 0
3 years ago
Read 2 more answers
I don't get this pls help
dmitriy555 [2]

Answer:

  d, e

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  a^-b = 1/a^b

__

In this case, it means the product is ...

  (6^1)(6^0)(6^-3) = 6^(1+0-3) = 6^-2 = 1/6^2 = 1/36

__

The 6 without an exponent is equivalent to 6^1, an exponent of 1.

The sum of the exponents is -2.

Add the exponents to simplify the expression.

The value of the expression is 1/36.

An equivalent is any expression that results in 6^-2. One such is (6^5)(6^-7).

__

Only the last two choices, d and e, apply.

3 0
4 years ago
Landon owns a hybrid SUV that can travel 400 miles on a 15 gallon tank of gas. Determine how many miles he can travel in 6 gallo
arlik [135]
Set this up as a proportion.

400/15 = x/6

Solve for x.

I just hope to help! :)
8 0
3 years ago
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