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Zigmanuir [339]
3 years ago
11

Find the sum to the equation of:

Mathematics
1 answer:
solong [7]3 years ago
5 0
\frac{a}{a^{2} - 4a + 4} + \frac{7}{a^{2} + 2a - 8} = \frac{a(a^{2} + 2a - 8)}{(a^{2} - 4a + 4)(a^{2} + 2a - 8)} + \frac{7(a^{2} - 4a + 4)}{(a^{2} - 4a + 4)(a^{2} + 2a - 8)} = \frac{a^{3} + 2a^{2} - 8a}{a^{4} - 2a^{3} - 12a^{2} + 40a - 32} + \frac{7a^{2} - 28a + 28}{a^{4} - 2a^{3} - 12a^{2} + 40a - 32} = \frac{a^{3} + 9a^{2} - 36a + 28}{a^{4} - 2a^{3} - 12a^{2} + 40a - 32}
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50 PTS ANSWER ALL &lt;3333333
11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

{h}^{2}  =  {6}^{2}  +  {8}^{2}

{h}^{2}  = 36+ 64

{h}^{2}  = 100

h =  \sqrt{100}

h = 10cm

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

{l}^{2}  +  {33}^{2}  =  {55}^{2}

{l}^{2}  =  {55}^{2}  -  {33}^{2}

{l}^{2}  = 1936

l =  \sqrt{1936}

l = 44cm

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the values to get,

d=\sqrt{( - 1-2)^2+(3- - 1)^2}

d=\sqrt{( - 3)^2+(4)^2}

d=\sqrt{9+16}

d=\sqrt{25}

d = 5

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

d=\sqrt{( - 3-2)^2+( - 3- 2)^2}

d=\sqrt{( - 5)^2+( - 5)^2}

d=\sqrt{25+25}

d=\sqrt{50}

d=5\sqrt{2}

Answer: D

8 0
2 years ago
Read 2 more answers
Complete the comparison: 5+4=?
atroni [7]
It could be 
5 + 4 = 3 squared, or
5 + 4 = 3 x3
4 0
2 years ago
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