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Zigmanuir [339]
3 years ago
11

Find the sum to the equation of:

Mathematics
1 answer:
solong [7]3 years ago
5 0
\frac{a}{a^{2} - 4a + 4} + \frac{7}{a^{2} + 2a - 8} = \frac{a(a^{2} + 2a - 8)}{(a^{2} - 4a + 4)(a^{2} + 2a - 8)} + \frac{7(a^{2} - 4a + 4)}{(a^{2} - 4a + 4)(a^{2} + 2a - 8)} = \frac{a^{3} + 2a^{2} - 8a}{a^{4} - 2a^{3} - 12a^{2} + 40a - 32} + \frac{7a^{2} - 28a + 28}{a^{4} - 2a^{3} - 12a^{2} + 40a - 32} = \frac{a^{3} + 9a^{2} - 36a + 28}{a^{4} - 2a^{3} - 12a^{2} + 40a - 32}
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