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3 years ago

Which of the t- values satisfy the following inequality?

Mathematics

1 answer:

Licemer1 [7]3 years ago

5 0

Answer:

A and B

Step-by-step explanation:

Given

8 > 3 + $\frac{t}{4}$

Isolate the term in t by subtracting 3 from both sides

5 > $\frac{t}{4}$ ( multiply both sides by 4 )

20 > t ⇒ t < 20

t = 12 and t = 16 are both less than 20

Hence A and B

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a car brought for sh 80,000 was sold through a dealer at a profit of 15% commission on the selling price.how much did the owner

Luba_88 [7]

80,000x.15 or 15% = 12,000

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4 years ago

use Taylor's Theorem with integral remainder and the mean-value theorem for integrals to deduce Taylor's Theorem with lagrange r

Vadim26 [7]

Answer:

As consequence of the Taylor theorem with integral remainder we have that

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt$

If we ask that $f$ has continuous $(n+1)$ th derivative we can apply the mean value theorem for integrals. Then, there exists $c$ between $a$ and $x$ such that

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x$

Hence,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .$

Thus,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$

and the Taylor theorem with Lagrange remainder is

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$ .

Step-by-step explanation:

5 0

3 years ago

A recipe calls for 3 1/2 cups of sugar. If you want to make only 1/3 of the recipe, how much sugar should you use?

Sav [38]

Answer: 1 1/6 cups of sugar

Step-by-step explanation:

First let’s convert 3 1/2 into an improper fraction: 7/2

Then we multiply 7/2 by 1/3: 7/2*1/3=7/6

Then finally we convert 7/6 into a mixed number, so your answer will be 1 1/6

3 0

3 years ago

Andrew has already played 32 minutes on his video game this morning and wants to play an additional 15 minutes on each of x game

belka [17]

Given :

Andrew has already played 32 minutes on his video game this morning and wants to play an additional 15 minutes on each of x games after school today.

To Find :

Which equation can be used to find y, the total minutes Andrew will play video games today.

Solution :

Number of minutes he play after school time, n = 15x .

Number of minutes already played, c = 32 .

So, total number of minutes he play games for today is :

y = n + c

y = 15x + 32

Therefore, equation which is useful to find number of minutes video game played per day is y = 15x + 32 .

8 0

3 years ago

Log (X) + 5 = 8 el valor de X es *

GaryK [48]

Log (x) = 3
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4 0

3 years ago