Ask question

Ask question

All categories

4 years ago

5

What is the monthly payment for a $20,230 loan at 11.5 percent for 20 years?

1 answer:

yKpoI14uk [10]4 years ago

4 0

The main formula is
M= P (i(1+i)^n) / <span>(1+i)^n) - 1
M: monthly payment
P: mortgage principale= </span><span> $20,230
i=montly interest, 11.5%=11.5/100=0.115, i= 0.115/12=0.009
n=number of months=12x20(years)=240 months

M= </span>$20,230(0.009(1.009)^240) / (1.009)^240-1=<span>$20,230 x 0.0077 / 8.58-1
M=$20.57

</span>

You might be interested in

Which is the slope of a line that is parallel to the line represented by the equation x-y=8

pychu [463]

Answer:

slope of parral line is same as slope of line its 1

5 0

3 years ago

Read 2 more answers

Which of these is a speed?

miskamm [114]

Answer:

50 miles per hour

Step-by-step explanation:

First one is a distance

Second one is time

Last one doesn't make sense

8 0

4 years ago

Read 2 more answers

A chef planning for a large banquet thinks that 2 out of every 5 dinner guests will order soup. 800 guests are going to be at th

Xelga [282]

Answer:

The Chef will prepare 320 soups for a large banquet

Step-by-step explanation:

chef thinks that 2 out of every 5 dinner guests will order soup

===> Order soup / total number of attender

= 2/5

Total guest = 800 ==> 4 people ordered soup is

2 /5 = x /800

cross multiplying

x = 2 x 800 / 5

= 320

The Chef will prepare 320 soups for a large banquet

8 0

4 years ago

Which formula is easier to use. Finding the area of a trapezoid or circle? Explain in detail with a minimum of 4 sentence

Scrat [10]

Answer: Circle, in my opinion

Step-by-step explanation:

Trapezoid Formula: (a+b/2)h

Circle Formula: πr*2

Solving a circle requires less steps than solving for a trapezoid would, so in my opinion, finding the area of a circle is easier than a trapezoid.

Hope this helps!

8 0

3 years ago

If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)

sweet-ann [11.9K]

Answer:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

Step-by-step explanation:

Given

$tan\theta = 3$

Required

Find

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$

Calculate $tan(\theta + \pi) \ and\ tan(\theta+2\pi)$

Using tan rule

$tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}$

So:

$tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + \pi) = \frac{tan\theta}{1 }$

$tan(\theta + \pi) = \tan\theta$

$tan(\theta+2\pi)$

$tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}$

$tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + 2\pi) = \tan\theta$ '

'So:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$ $= tan\theta +tan\theta +tan\theta$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

4 0

3 years ago