A cylinder has volume 78cm^3. What is the volume of a cone with the same radius and height?

A car travels at a rate of 45 miles per hour for 5 hours. Let y be the distance, in miles, the car travels for a given amount of

Nuetrik [128]

Answer:

0 ≤ x ≤ 5

Step-by-step explanation:

I used the Desmos calculator

6 0

3 years ago

Z-12=4 what is Z worth?

Gnoma [55]

Answer:

Z=16

Step-by-step explanation:

just add 12 to both sides so you are left with only Z on one side

5 0

3 years ago

Read 2 more answers

In a scale model of a table, 1 centimeter represents 8 inches.

Trava [24]

Answer:

(a): 6 centimeters

(b): 72 inches

Step-by-step explanation:

Rule: From centimeters to inches, multiply centimeters × 8

so from inches to centimeters, divide inches by 8

Scale:

1 cm : 8 in

? cm : 48 in

6 cm : 48 in

Scale:

? in : 9 cm

72 in : 9 cm

8 0

3 years ago

Use the equation a = IaIâ

german

Answer:

a) $\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }$

b) $\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }$

c) $\:\:=7\cdot \frac{\:\:}{7}$

Step-by-step explanation:

a) Let a=<2,1,-3>

The magnitude of a is $|a|=\sqrt{2^2+1^2+(-3)^2}$

$|a|=\sqrt{4+1+9}=\sqrt{14}$

The unit vector in the direction of a is

$\hat{a}=\frac{\:\:}{\sqrt{14} }$

Using the relation $a=|a|\hat{a}$ , we have

$\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }$

b) Let a=2i - 3j + 4k

$|a|=\sqrt{2^2+(-3)^2+4^2}$

$|a|=\sqrt{4+9+16}=\sqrt{29}$

$\hat{a}=\frac{\:\:}{\sqrt{29} }$

Using the relation $a=|a|\hat{a}$ , we have

$\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }$

c) Let us first find the sum of <1, 2, -3> and <2, 4, 1> to get:

<1+2, 2+4, -3+1>=<3, 6, -2>

Let a=<3, 6, -2>

The magnitude is

$|a|=\sqrt{3^2+6^2+(-2)^2}$

$|a|=\sqrt{9+36+4}=\sqrt{49}=7$

The unit vector in the direction of a is

$\hat{a}=\frac{\:\:}{7}$

Using the relation $a=|a|\hat{a}$ , we have

$\:\:=7\cdot \frac{\:\:}{7}$

5 0

3 years ago

Look at the table of values below.

Natalka [10]

Answer:

A. y = 1 - 2x

The equation y = 1 - 2x is represented by the table.

Step-by-step explanation:

In this question you are trying to find out which is the right equations that belongs to the table of values.

For any streight line, you need the minimum of two points (x,y) to be able to draw a line that accounts for all points on that line...

If you substitute x = 1 in any of the equations, the outcome should be -1 because that is given in the table.

So try it and you will you find solely based on one of the first value that, the equations in A. and C. could be valid, because the point with coordinates (1, -1) is on the line A. and also on C.

At this time you can totally discard equations B an D because the value of y = -1 is not the outcome if you substitute x = 1. You can absolutely cross out answers B an D. Please understand what a timesaver this is; for the next substitution you only need to subsymtitue one extra coordinate (x,y) and you only have to substitute it only in equations A and C.

Try one more point, to choose between answer A and answer C. Just pick the easiest value in the table.

Please understand that you could pick eighter the x value OR YOU COULD choose the y value. It just does not matter, because the coordinate (x,y) is a pair of two numbers which are bound together by the equation given and also by all values in the table... The question remains, how fast can you distinguish which is the right equation....

After substituting another value from the table, you find that only equation A. is valid and not C (and you already discarded answers B an D remember)....

So the equation y = 1 - 2x is represented by the table, which is answer A.

Although this is a lot of text explaining the simple steps of substituting a value of the table an checking if the coordinate is a member of the equation, I hope it will save you a lot of time in the future!

8 0

3 years ago