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3 years ago

13

A cylinder has volume 78cm^3. What is the volume of a cone with the same radius and height?

1 answer:

Sveta_85 [38]3 years ago

3 0

It’s a shape, that’s the same volume a shape
It’s correct

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A box contains 16 cherry fruit chews,15 beach fruit chews ,and 12 plum fruit chews .which two flavors are in the ratio 5 to 4

olga_2 [115]

The beach (wt_f) and the plum chews.

7 0

3 years ago

Read 2 more answers

Determine whether the origin is included in the shaded region and whether the shaded region is above or below the line for the g

kati45 [8]

Answer:

Option: D is correct.

Step-by-step explanation:

since we are given a inequality as:

$y$

Clearly from the graph of the following inequality we could see that the origin is included in the shaded region and the shaded area is below the line.

Also it could be seen that if we put the origin points i.e. (0,0) in the inequality than 0<2 and the condition is true and hence origin is included in the shaded area.

Hence, option D is true.

6 0

3 years ago

Is the square root of 34 a rational number

serious [3.7K]

Answer:

No

Step-by-step explanation:

The square root of 34 does not multiply by itself

4 0

3 years ago

Read 2 more answers

PLEASE HELP I tried on my own but it’s not there

aev [14]

Step-by-step explanation:

I think the answer is 34°

4 0

3 years ago

Can please someone help me? The question is in the picture. Thank you

maxonik [38]

Answer:

C. $9\pi$

Step-by-step explanation:

We proceed to solve for $x$ by the Pythagorean Theorem:

$(x+1)^{2} = (x-1)^{2} + (2\cdot x - 4)^{2}$ (1)

$x^{2} + 2\cdot x + 1 = (x^{2}-2\cdot x + 1) + (4\cdot x^{2}-16\cdot x + 16)$

$x^{2} + 2\cdot x + 1 = 5\cdot x^{2}-18\cdot x + 17$

$4\cdot x^{2} -20\cdot x + 16 = 0$

$(2\cdot x)^{2} -10\cdot (2\cdot x) + 16 = 0$

$(2\cdot x -8)\cdot (2\cdot x -2) = 0$

There are two different solutions:

$x_{1} = 4$ , $x_{2} = 1$

A solution of $x$ is considered realistic when the length of every side of the triangle is a not negative number.

$x_{1} = 4$

$UV = 2\cdot (4) - 4$

$UV = 4$

$WU = 4 - 1$

$WU = 3$

$WV = 4 + 1$

$WV = 5$

$x_{2} = 1$

$UV = 2\cdot (1) - 4$

$UV = -2$

$WU = 1 - 1$

$WU = 0$

$WV = 1 + 1$

$WV = 2$

The only realistic set of solutions is for $x = 4$ , and the radius of the circle is represented by the line segment $WU$ : $r = 3$

And the area of the circle ( $A$ ) is calculated from the following formula:

$A = \pi\cdot r^{2}$

$A = \pi\cdot (9)$

$A = 9\pi$

The correct answer is C.

6 0

2 years ago