How many hundreds tens and ones have 423

Mathematics

2 answers:

Gnom [1K]3 years ago

7 0

Four hundreds two tens and three ones

EleoNora [17]3 years ago

6 0

Four 100's , two 10's , a three 1's .

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Does this scatter plot show a positive trend a negative trend or no trend

maw [93]

The dots are moving in a downward direction from left to right, so it is a negative trend.

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2 years ago

A Pedro le dieron de aguinaldo el triple de lo que recibe de sueldo en un mes. Si pagó una deuda de $4500.00 y aún le quedaron $

Kitty [74]

Answer:

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3 years ago

13 + k3= 11 Show work pls

zaharov [31]

13+3k=11
-Move constant to the right-hand side and change its sign
3k=11-13

Calculate the difference
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3 years ago

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 6x(1/3) + 3x(4/3). You must justi

stealth61 [152]

Applying our power rule gets us our first derivative,

$\rm f'(x)=6\frac13x^{-2/3}+3\cdot\frac43x^{1/3}$

simplifying a little bit,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

looking for critical points,

$\rm 0=2x^{-2/3}+4x^{1/3}$

We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.

$0=2x^{-2/3}\left(1+2x\right)$

When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.

Then apply your Zero-Factor Property,

$\rm 0=2x^{-2/3}\qquad\qquad\qquad 0=(1+2x)$

and solve for x in each case to find your critical points.

Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.

Let's come back to this,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

and take our second derivative.

$\rm f''(x)=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Looking for inflection points,

$\rm 0=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Again, pulling out the smaller power of x, and fractional part,

$\rm 0=-\frac43x^{-5/3}\left(1-x\right)$

And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.

Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.

8 0

3 years ago

Which are steps in the process of completing the square used to solve the equation 3 – 4x = 5x2 – 14x? Check all that apply.

avanturin [10]

Add 4x over to 14x, 3=5x2- 18x then add 18x to the other side 3+ 18x= 5x2then divided each side by 5,( 3+18x/5=x2) then square root each side the answer to x would be the square root of 3+18x/5

6 0

3 years ago

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