QUICK !!! FAST 15 POINTS I NEED HELP!!!!!
2 answers:
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Answer:
Step-by-step explanation:
Given
There are 52 cards in total
there are total of 13 pairs of same cards with each pair containing 4 cards
Probability of getting a pair or three of kind card=1-Probability of all three cards being different
Probability of selecting all three different cards can be find out by selecting a card from first 13 pairs and remaining 2 cards from remaining 12 pairs i.e.
for first card there are 52 options after choosing first card one pair is destroyed as we have to select different card .
For second card we have to select from remaining 12 pairs i.e. 48 cards and so on for third card.
Required Probability is
In 1)
Line 1 has following coordinates.
(0,0) ; (1,-2) ; (2,-4)
Line 2 has following coordinates.
(0,0) ; (1,0.5) ; (2,1)
Line 3 has following coordinates.
(0,1) ; (1,1.5) ; (2,2)
If you'll draw the lines, you'll observe that Line 1 is perpendicular to Line 2 and Line 3 and Line 2 and Line 3 are parallel to each other.
So,
Option D will be correct.
Line 1 has following coordinates.
(0,0) ; (1,-2) ; (2,-4)
Line 2 has following coordinates.
(0,0) ; (1,0.5) ; (2,1)
Line 3 has following coordinates.
(0,1) ; (1,1.5) ; (2,2)
If you'll draw the lines, you'll observe that Line 1 is perpendicular to Line 2 and Line 3 and Line 2 and Line 3 are parallel to each other.
So,
Option D will be correct.