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4 years ago

0.4/0.01=40 how does the quotient relate to divide

Mathematics

1 answer:

valkas [14]4 years ago

8 0

Quotient is the answer of the division
0.4/0.01 = 40 x 10 = 4/0.1 = 40 x 10 = 40/1 = 40

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Find the area of the figure.

exis [7]

Answer:

the area is 384 in.

Step-by-step explanation:

split the figure in two pieces

12 x 12 = 144 in.

20 x 12 = 240 in.

144 + 240 = 384 in.

the total Area of the figure Is 384 in.

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3 years ago

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Is 6 /1.2 a rational number

olasank [31]

Answer:

yes

Step-by-step explanation:

A rational number can be expressed in the form

$\frac{a}{b}$ ← where a, b are integers

Given

$\frac{6}{1.2}$ ← multiply numerator/ denominator by 10

= $\frac{60}{12}$ = 5 = $\frac{5}{1}$ ← a rational number

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3 years ago

In horse racing, a trifecta is a bet that the first three finishers in a race are selected, and they are selected in the corre

Evgesh-ka [11]

The correct answer is D

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3 years ago

Please help with this math problem! The intersection of GK and HL is point P. Which triangle must be an isosceles triangle? *loo

Whitepunk [10]

None of the triangles listed has two equal base angles or two equal side lengths, therefore: D. No triangle is isosceles.

<h3>Properties of an Isosceles Triangle</h3>

An isosceles triangle has two base angles having equal angle measure.
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brainly.com/question/11884412

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3 years ago

A line segment AB has the coordinates A (2,3) AND B ( 8,11) answer the following questions (1) What is the slope of AB? (2) What

GalinKa [24]

Answer:

(1) The slope of the line segment AB is 1. $\bar 3$

(2) The length of the line segment AB is 10

(3) The coordinates of the midpoint of AB is (5, 7)

(4) The slope of a line perpendicular to the line AB is-0.75

Step-by-step explanation:

The coordinates of the line segment AB are;

A(2, 3) and B(8, 11)

(1) The slope of a line segment is given by the following equation;

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Where;

(x₁, y₁) and (x₂, y₂) are two points on the line segment

Therefore;

The slope, m, of the line segment AB is given as follows;

A(2, 3) = (x₁, y₁) and B(8, 11) = (x₂, y₂)

$Slope, \, m_{AB} =\dfrac{11-3}{8-2} = \dfrac{8}{6} = 1 \frac{1}{3} = 1.\bar3$

The slope of the line segment AB = 1. $\bar 3$

(2) The length, l, of the line segment AB is given by the following equation;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

Therefore, we have;

$l_{AB} = \sqrt{\left (11-3 \right )^{2}+\left (8-2 \right )^{2}} = \sqrt{64 +36} = 10$

The length of the line segment AB is 10

(3) The coordinates of the midpoint of AB is given as follows;

$Midpoint, M = \left (\dfrac{x_1 + x_2}{2} , \ \dfrac{y_1 + y_2}{2} \right )$

Therefore;

$Midpoint, M_{AB} = \left (\dfrac{2 + 8}{2} , \ \dfrac{3 + 11}{2} \right ) = (5, \ 7)$

The coordinates of the midpoint of AB is (5, 7)

(4) The relationship between the slope, m₁, of a line AB perpendicular to another line DE with slope m₂, is given as follows;

$m_1 = -\dfrac{1}{m_2}$

Therefore, the slope, m₁, of the line perpendicular to the line AB, that has a slope m₂ = 4/3 = 1. $\bar 3$ is given as follows;

$m_1 = -\left (\dfrac{1}{\frac{4}{3} } \right ) = -\dfrac{3}{4} = -0.75$

The slope, m₁, of the line perpendicular to the line AB is m₁ = -0.75.

8 0

3 years ago