All categories

3 years ago

I don't btgcygljhbihlihnjknkl;n

Mathematics

2 answers:

Digiron [165]3 years ago

7 0

Yeah honestly same it’s ok tho

jekas [21]3 years ago

6 0

Homework do be like that

You might be interested in

What is the answer <br> (x³)^4

Fofino [41]

Answer:

the answer is x^12

Step-by-step explanation:

multiply 3 by 4 and you get 12

8 0

3 years ago

Read 2 more answers

Determine the vertex of the function f(x) = 3(x - 2)^2 + 1.

Sliva [168]

Answer:

The vertex is at (2,1)

Step-by-step explanation:

The vertex form of a quadratic is

y = a(x-h)^2 +k where (h,k) is the vertex

f(x) = 3(x - 2)^2 + 1.

The vertex is at (2,1)

4 0

3 years ago

Tristan made a one-sample zzz interval for a proportion and used the critical value z^*=2.054z

Iteru [2.4K]

Answer:

C) 96%

Step-by-step explanation:

5 0

3 years ago

The probability of event A is P(A) = 0.25. What is the probability that event A does NOT occur?

Kryger [21]

Answer:

.75

Step-by-step explanation:

75%

because it will give 100

6 0

3 years ago

The width of a rectangle is 5 units less than the length. The area of the rectangle is 6 units. What is the width, in units, of

Readme [11.4K]

Answer:

The width of rectangle is 1 unit.

Step-by-step explanation:

Given:

The area of rectangle is 6 units and its width is 5 units less than the length.

So, to find the width of rectangle.

Let the length be $x$ and the width be $x-5$ .

Now, to find the width we put the formula of area of rectangle:

Area = length × width

$6= x\times (x-5)$

$6=x^{2}-5x$

$0=x^{2}-5x-6$

$0=x^{2}-6x+x-6$

$0=x(x-6)+1(x-6)$

$0=(x-6)(x+1)$

<em>On solving equation we get:</em>

$x-6=0, x+1=0$

Therefore, we take the value x=6 as it is positive value:

$x-6=0$

$x=6$

So, the width of rectangle:

Width = $x-5$

= $6-5$

= $1$

Therefore, the width of rectangle is 1 unit.

8 0

3 years ago