That is height
h=16t^2+16t+480
when h=0 is when it hits the water
0=16t^2+16t+480
undistribbute 16 for ease
0=16(t^2+t+30)
16*0=0 so assume
t^2+t+30=0
factor
(t+6)(t-5)=0
set to zero
t+6=0
minus 6
t=-6
false, since you cannot have negative time
t-5=0
add 5
t=5
at t=5 she hits the water
5 seconds
Answer:
∠6 > ∠3 is TRUE.
Step-by-step explanation:
We know that acute angle is less than 90 degree while obtuse angle is more than 90 degree. By looking at the given angles, we can easily determine which angle is obtuse or acute. then we can decide which angle is bigger to find the answer.
∠10 > ∠7
FALSE;
Because∠10 is acute while ∠7 is obtuse.
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∠6 > ∠3
TRUE;
Because∠3 is acute while ∠6 is obtuse.
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∠9 > ∠11
FALSE;
Because∠9 is acute while ∠11 is obtuse.
------------
∠8 > ∠11
FALSE;
Because∠8 is acute while ∠11 is obtuse.
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If you use a distributive or multiply is all kind a same
Answer with Step-by-step explanation:
We are given that
Total dogs=24
Total cats=18
Total animals=24+18=42
Male dogs=8
Male cats=6
Total male animals=8+6=14
Total female animals=42-14=28
Female cats=18-6=12
Dogs female=24-8=16
a.We have to find the probability that the pet is male, given that it is cat.
It means we have to find P(Male/cat)
Conditional probability: 
P(Cat)=
P(male/cat)=
b.
c.P(Dog)=
