Question

The area of a playground is 20 square yards. The length of the playground is 5 times longer than its width. Find the length and width of the playground.
length = 1 yd, width = 20 yd
length = 2 yd, width = 10 yd
length = 10 yd, width = 2 yd
length = 20 yd, width = 1 y

Answer 1

The answer is length = 10 yd, width = 2 yd
proof 
The length of the playground is 5 times longer than its width, it means
l=5w, but 10= 2x5 so we can write l= 5w, 
and Area = 20 =l x w = (5x2) x 2 =20