Answer: One tail test.
Step-by-step explanation:
Given : A sample of 36 observations is selected from a normal population. The sample mean is 12, and the population standard deviation is 3.
Also, The set of hypothesis to conduct a test :-
![H_0:\mu\leq10\\\\H_1:\mu>10](https://tex.z-dn.net/?f=H_0%3A%5Cmu%5Cleq10%5C%5C%5C%5CH_1%3A%5Cmu%3E10)
The kind of test need to perform is dependent upon the alternative hypothesis.
Since, the alternative hypothesis is one tailed (right-tailed), so the test is one tail test.
Answer:
(-6,-5)
Step-by-step explanation:
X+y=-11
solve for x
x=-11-y
substiute x value into 2nd equation
2x-3y=3
2(-11-y)-3y=3
-22-2y-3y=3
-5y=25
y=-5
substitute -5 for y in either equation to find x
x+y=-11
x+-5=-11
x=-6
Answer:
Correct answer: The third answer is correct
Step-by-step explanation:
The domain of each function is defined by observing the behavior of the function from left to right by following the growth of numbers on the x axis of real numbers.
In the same way, the range of each function is defined by observing the behavior of the function from the bottom y axis upwards by following the growth of numbers on the y axis of real numbers.
The given function extends from negative infinite to positive infinite on the x axis and that is the domain of this function.
The minimum of a given function is 4, which means that the function exists from 4 upwards and that is the range of the function.
Domain; all real numbers or x ∈ ( -∞ , + ∞)
Range: ( y ≥ 4 )
God is with you!!!
1cm = 10mm
15.24cm x 10 = 152.4mm
Hope this helps!!!
<h3>Answer :- </h3>
<h3>Solution :- </h3>
- Let the age of victor be X .
- and, the age of Mr.Smith be = 81 + x
♧ <em>So, after 3 years = x+81 +3</em>
- 81 + 3 + x = 4 ( x + 3 )
- 84 + x = 4x + 12
♧ <em>now grouping the variables and constants together we get,</em>
- 4x-x=84-12
- 3x = 72
- x = 72/3
- x = 24
♧ <em>Thus, Victor's present age is 24 yrs.</em>
<em>H</em><em>o</em><em>p</em><em>e</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>ya</em><em> </em><em>~</em><em> </em>