<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20x%2B3-2x%3D-%5Cfrac%7B1%7D%7B4%7D%20%2B%5Cfrac%7B1%7D%7B2%7D%20x%2B5"

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3 years ago

id="TexFormula1" title="\frac{3}{4} x+3-2x=-\frac{1}{4} +\frac{1}{2} x+5" alt="\frac{3}{4} x+3-2x=-\frac{1}{4} +\frac{1}{2} x+5" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Shtirlitz [24]3 years ago

4 0

Your answer would be: x= -1

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Andy completes the square for the equation x2 + 6x - 8 = 0. Which of the following equations reveals the vertex of the parabola?

Stolb23 [73]

If the equation $x^2+6x-8$ has undergo completing the square, the answer would be:
$x^2+6x-8
$
$x^2+6x+9-8-9$
**In this example, since 6x is the middle term, what comes to my mind is the polynomial (x+3) because 2ab results into 6x. [from the special products lesson $(a+b)^2=a^2+2ab+b^2$ ]
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So if the equation is equal to y, then this equation's
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3 0

3 years ago

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Solve for x: 6 x2 + 2x - 3 2 = 0

Zigmanuir [339]

I think the answer is 10 because:

6x2=12

12+2x-32=0

make the like terms together = 12-32+2x=0

= -20+2x=0

again make the like terms together = 2x=0+20 [sign changes when it goes to the other side]

so, 2x=20

x=20/2 [ multiplication will change into division when it goes to the other side]

therefore x=10

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3 years ago

Write the equation of a line that is perpendicular to y=3x-2 that passes trough the point (-9,5)

ElenaW [278]

$\huge\boxed{y-5&=-\frac{1}{3}(x+9)}$

First, we'll find the slope of the new line. The first line has a slope of $3$ . Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by $-1$ ) to get $-\frac{1}{3}$ for the new slope.