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2 years ago

△ABC is reflected to form △A'B'C' .

Mathematics

2 answers:

Leno4ka [110]2 years ago

7 0

Reflection across the y-axis

Pepsi [2]2 years ago

3 0

Answer:

Option B.

Step-by-step explanation:

It is given that △ABC is reflected to form △A'B'C' .

It is given that the vertices of triangle ABC are A(4,1), B(6,3) and C(2,4).

From the given figure it is clear that vertices of triangle A'B'C' are A'(-4,1), B'(-6,3) and C(-2,4).

The relation between preimage and image is defined by the rule

$(x,y)\rightarrow (-x,y)$

Reflection across y-axis represented by the above rule.

It means the △ABC is reflected across the y-axis to form △A'B'C' .

Therefore, the correct option is B.

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The dot product of u with itself is 12. What is the magnitude of u?

Brilliant_brown [7]

Dot product is
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In our case
u*u =|u|*|u|*cos 0
u*u =|u|*|u|
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3 years ago

Estimate the solution to the system of equations. asap, please!! I will mark for brain list

Darya [45]

Answer:

(1 $\frac{1}{3}$ , 2 $\frac{1}{3}$ )

Step-by-step explanation:

Given the 2 equations

7x - y = 7 → (1)

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14x - 2y = 14 → (3)

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Substituting in (2)

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3 years ago

Two cards are drawn without replacement from a standard deck of 52 playing cards. What is the probability of choosing a king and

STALIN [3.7K]

Answer:

0.0181 probability of choosing a king and then, without replacement, a face card.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability of choosing a king:

There are four kings on a standard deck of 52 cards, so:

$P(A) = \frac{4}{52} = \frac{1}{13}$

Probability of choosing a face card, considering the previous card was a king.

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$P(B|A) = \frac{12}{51}$

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$P(A \cap B) = P(A)P(B|A) = \frac{1}{13} \times \frac{12}{51} = \frac{1*12}{13*51} = 0.0181$

0.0181 probability of choosing a king and then, without replacement, a face card.

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3 years ago

Two faulty machines, M1 and M2, are repeatedly run synchronously in parallel (i.e., both machines execute one run, then both exe

leonid [27]

The event that either M1 or M2 fails has probability

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by the addition rule. Failure events are independent, so

$P(M_1\text{ and }M_2\text{ both fail})=P(M_1\text{ fails})P(M_2\text{ fails})$

so that

$P(M_1\text{ fails or }M_2\text{ fails})=p_1+p_2-p_1p_2$

Denote this probability by $p$ . Then $X$ follows a geometric distribution with this parameter $p$ and has density

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3 years ago

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Answer:

Step-by-step explanation:

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total is 224.7cl

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3 years ago

△ABC is reflected to form ​​ ​ △A'B'C' ​.

△ABC is reflected to form △A'B'C' .