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anyanavicka [17]
3 years ago
8

Who is the primary audience for demonstrations of game prototypes made by the developer?

Computers and Technology
1 answer:
padilas [110]3 years ago
5 0

Answer:

the tester

Explanation:

When a video game is playable the first audience to test these prototypes are the tester, these people have to test all the game, and they have say all the information about errors, issues, bugs, and any difficulty to resolve these problems in a final video game's version, in this way the complete game arrives to the final audience.

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Miguel owns a tile business. He has two employees who work in a small office. One answers phones and schedules appointments. Ano
Margaret [11]

Answer: I believe the answer is LANs

Explanation: Because of the use of two computers, small office, and same printer/fax machine, LANs would be more accurate due to its smaller region.

8 0
3 years ago
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The advancement in speed of transportation is attributed to invention of this device
morpeh [17]
The automobile is the invention
3 0
3 years ago
#A year is considered a leap year if it abides by the #following rules: # # - Every 4th year IS a leap year, EXCEPT... # - Every
lara [203]

Answer:

To check if the year comes under each 100th year, lets check if the remainder when dividing with 100 is 0 or not.

Similarly check for 400th year and multiple 0f 4. The following C program describes the function.

#include<stdio.h>

#include<stdbool.h>

bool is_leap_year(int year);

void main()

{

int y;

bool b;

 

printf("Enter the year in yyyy format: e.g. 1999 \n");

scanf("%d", &y);     // taking the input year in yyyy format.

 

b= is_leap_year(y);  //calling the function and returning the output to b

if(b==true)

{

 printf("Thae given year is a leap year \n");

}

else

{

 printf("The given year is not a leap year \n");

}

}

bool is_leap_year(int year)

{

if(year%100==0)   //every 100th year

{

 if(year%400==0)   //every 400th year

 {

  return true;

 }

 else

 {

  return false;

 }

}

if(year%4==0)  //is a multiple of 4

{

 return true;

}

else

{

 return false;

}

}

Explanation:

Output is given as image

5 0
3 years ago
Which Windows installation method requires that you manually rename computers after the installation?​
levacccp [35]

Answer:

Command line

Explanation:

  • After installation of the machine one needs to manually rename the computer. This can be done through the start then settings, then system, and select rename the PC in the right-hand side column.
3 0
3 years ago
Write a program that will predict the size of a population of organisms. The program should ask the user for the starting number
sineoko [7]

Answer:

// using c++ language

#include "stdafx.h";

#include <iostream>

#include<cmath>

using namespace std;

//start

int main()

{

 //Declaration of variables in the program

 double start_organisms;

 double daily_increase;

 int days;

 double updated_organisms;

 //The user enters the number of organisms as desired

 cout << "Enter the starting number of organisms: ";

 cin >> start_organisms;

 //Validating input data

 while (start_organisms < 2)

 {

     cout << "The starting number of organisms must be at least 2.\n";

     cout << "Enter the starting number of organisms: ";

     cin >> start_organisms;

 }

 //The user enters daily input, here's where we apply the 5.2% given in question

 cout << "Enter the daily population increase: ";

 cin>> daily_increase;

 //Validating the increase

 while (daily_increase < 0)

 {

     cout << "The average daily population increase must be a positive value.\n ";

     cout << "Enter the daily population increase: ";

     cin >> daily_increase;

 }

 //The user enters number of days

 cout << "Enter the number of days: ";

 cin >> days;

 //Validating the number of days

 while (days<1)

 {

     cout << "The number of days must be at least 1.\n";

     cout << "Enter the number of days: ";

     cin >> days;

 }

 

 //Final calculation and display of results based on formulas

 for (int i = 0; i < days; i++)

 {

     updated_organisms = start_organisms + (daily_increase*start_organisms);

     cout << "On day " << i + 1 << " the population size was " << round(updated_organisms)<<"."<<"\n";

     

     start_organisms = updated_organisms;

 }

 system("pause");

  return 0;

//end

}

Explanation:

6 0
3 years ago
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