Question

Write a loop that reads positive integers from standard input and that terminates when it reads an integer that is not positive. After the loop terminates, it prints out, on a single line and separated by a single space, the sum of all the even integers read and the sum of all the odd integers read. python

Answer 1

Answer:

The program to this question as follows:

Program:

#defining variable and assign value

odd=0  

even=0  

i=1  

print('Input 0 after inserting all number: ') #print message

while i>0: #define loop for check inserting and add all number

   i=int(input()) #input value by user end

   if (i< 0): #check value is not positive

       break

   if ((i % 2)==0and(i>0)): #check even number condition

       even=even+i #add even numbers

   if ((i % 2)!=0and(i>0)): #check odd number condition

       odd=odd+i #add odd numbers

print ('Sum of Even number:',even,'and','Sum of Odd number:',odd) #print value

Output:

Input 0 after inserting all number:  

1

2

3

5

7

0

Sum of Even number: 2 and Sum of Odd number: 16

 Explanation:

In the above python program, three variable is defined, that is "even, odd and i", in which "even and odd" variable assign value that is "0", and the variable i is used for inserting elements from user. In the next line a while loop is defined that inserts numbers in variable "i", in this loop, 3 if block is used that can be defined as follows:

• In first if block variable "i", checks that value is non-positive number if this condition is true, it will break the loop.
• In second if block this block check even number condition and add in even variable.
• In third, if block this block check odd number condition and add in odd variable.  

End of the loop we use print function that prints the sum of even numbers and odd numbers.