Answer:
Dimensions 30 in x 30 in x 15 in
Surface Area = 2,700 in²
Step-by-step explanation:
Let 'r' be the length of the side of the square base, and 'h' be the height of the bin. The volume is given by:

The total surface area is given by:

Rewriting the surface area function as a function of 'r':

The value of 'r' for which the derivate of the surface area function is zero, is the length for which the area is minimized:
![A=54,000*r^{-1}+r^2\\\frac{dA}{dr}=0= -54,000*r^{-2}+2r\\\frac{54,000}{r^2}=2r\\ r=\sqrt[3]{27,000}\\r=30\ in](https://tex.z-dn.net/?f=A%3D54%2C000%2Ar%5E%7B-1%7D%2Br%5E2%5C%5C%5Cfrac%7BdA%7D%7Bdr%7D%3D0%3D%20-54%2C000%2Ar%5E%7B-2%7D%2B2r%5C%5C%5Cfrac%7B54%2C000%7D%7Br%5E2%7D%3D2r%5C%5C%20r%3D%5Csqrt%5B3%5D%7B27%2C000%7D%5C%5Cr%3D30%5C%20in)
The value of 'h' is:

The dimensions that will ensure the minimum surface area are 30 in x 30 in x 15 in.
The surface area is:

Answer:
-86
Step-by-step explanation:
simplify each equation as much as possible
f(x)= 4x(2+9) add
4x(11) multiply
f(x)=44x
substitute given numbers into each equation
44(-2)=-88 3(4)-14= 12-14=-2
combine equations
-88-(-2)= -86 add since you are subtracting a negative number
41 lb
work: 65 - 24 = 41
you're welcome
I’m not sure but maybe true
We have to start by creating an equation.
Cost of System = x
Cost of games = 3x
Thus x + 3x = $500
Now we find x.
4x = 500,
x = 500/4 = 125
So the system is 125,
The games, 125*3 = 375